Your answer should be 32m^5
(2m)(2m)
4m^2(2m)
8m^3(2m)
16m^4(2m)
32^5
Multiply 2.5 by 18 to get 45, which is the answer. 45 yards of ribbon for 18 balloons
Answer:
![Time = 1.978\ min](https://tex.z-dn.net/?f=Time%20%3D%201.978%5C%20min)
Step-by-step explanation:
Given
--- Flow rate of the shower
--- Drain rate of the bathtub
-- Bathtub size
Required
Determine the maximum time of shower
First, we calculate the rate at which the bathtub fills.
![R_3 = R_1 + R_2](https://tex.z-dn.net/?f=R_3%20%3D%20R_1%20%2B%20R_2)
![R_3 = 2.25 + 20.5](https://tex.z-dn.net/?f=R_3%20%3D%202.25%20%2B%2020.5)
![R_3 = 22.75gal/min](https://tex.z-dn.net/?f=R_3%20%3D%2022.75gal%2Fmin)
The maximum time of shower is:
![Time = \frac{Size}{R_3}](https://tex.z-dn.net/?f=Time%20%3D%20%5Cfrac%7BSize%7D%7BR_3%7D)
![Time = \frac{45gal}{22.75gal/min}](https://tex.z-dn.net/?f=Time%20%3D%20%5Cfrac%7B45gal%7D%7B22.75gal%2Fmin%7D)
Answer:
-2
Step-by-step explanation:
-9x+1 = -x+17
1-17 = -x+9x
-16 = 8x
-16/8 = x
-2 = x
-5.8c + 4.2 - 3.1 + 1.4c = -4.4c +1.1
Hope this helps! Ask me any questions if needed :)