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RUDIKE [14]
3 years ago
14

At a construction site, there are constant arguments and conflicts amongst workers of different contractors and sub-contractors.

The construction manager is unable to bring the situation under control. As a result, there’s a delay in project completion. Which skill is the construction manager lacking in? A. communication B. technical C. planning D. interpersonal E. IT
Engineering
1 answer:
jeyben [28]3 years ago
6 0

Interpersonal skill is required by the construction manager to resolve the arguments and conflicts among workers and between the contractors.

Answer: Option(d)

<u>Explanation:</u>

  • Interpersonal skills are a set of behavioral action that involves the person to interact freely with other peoples effectively.
  • A person before interacting with others should pay attention, listen to their words and give responses to them after they finish with their arguments.
  • In the above answer, the construction manager has to develop interpersonal skills to resolve the issues, conflicts, and arguments raised by his employees.
  • The manager must listen to their needs and demands possessed and should take necessary action in resolving the issues.
  • For that, the manager has to interact freely and effectively with their employees in resolving the issues.
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A 500-km, 500-kV, 60-Hz, uncompensated three-phase line has a positivesequence series impedance. z = 5 0.03 1 + j 0.35 V/km and
Anni [7]

Answer:

A) 282.34 - j 12.08 Ω

B) 0.0266 + j 0.621 / unit

C)

A = 0.812 < 1.09° per unit

B =  164.6 < 85.42°Ω  

C =  2.061 * 10^-3 < 90.32° s

D =  0.812 < 1.09° per unit

Explanation:

Given data :

Z ( impedance ) = 0.03 i  + j 0.35 Ω/km

positive sequence shunt admittance ( Y ) = j4.4*10^-6 S/km

A) calculate Zc

Zc = \sqrt{\frac{z}{y} }  =  \sqrt{\frac{0.03 i  + j 0.35}{j4.4*10^-6 } }    

    = \sqrt{79837.128< 4.899^o}   =  282.6 < -2.45°

hence Zc = 282.34 - j 12.08 Ω

B) Calculate  gl

gl = \sqrt{zy} * d  

 d = 500

 z = 0.03 i  + j 0.35

 y = j4.4*10^-6 S/km

gl =  \sqrt{0.03 i  + j 0.35*  j4.4*10^-6}  * 500

   = \sqrt{1.5456*10^{-6} < 175.1^0} * 500

   = 0.622 < 87.55 °

gl = 0.0266 + j 0.621 / unit

C) exact ABCD parameters for this line

A = cos h (gl) . per unit  =  0.812 < 1.09° per unit ( as calculated )

B = Zc sin h (gl) Ω  = 164.6 < 85.42°Ω  ( as calculated )

C = 1/Zc  sin h (gl) s  =  2.061 * 10^-3 < 90.32° s ( as calculated )

D = cos h (gl) . per unit = 0.812 < 1.09° per unit ( as calculated )

where :  cos h (gl)  = \frac{e^{gl} + e^{-gl}  }{2}

             sin h (gl) = \frac{e^{gl}-e^{-gl}  }{2}

     

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Answer:

La  C

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2) The switch in the circuit below has been closed a long time. At t=0, it is opened.
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Answer:

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Explanation:

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The time constant is L/R = 0.20/20 = 0.01 seconds. Then the decaying current is described by ...

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Answer:

Decreased risk of structure failure

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