At a construction site, there are constant arguments and conflicts amongst workers of different contractors and sub-contractors.
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Answer:
0.2 kcal/mol is the value of for this reaction.
Explanation:
The formula used for is:
where,
= Gibbs free energy for the reaction
= standard Gibbs free energy
R =Universal gas constant
T = temperature
Q = reaction quotient
k = Equilibrium constant
We have :
Reaction quotient of the reaction = Q = 46
Equilibrium constant of reaction = K = 35
Temperature of reaction = T = 25°C = 25 + 273 K = 298 K
R = 1.987 cal/K mol
1 cal = 0.001 kcal
0.2 kcal/mol is the value of for this reaction.
Answer:
The conversion in the real reactor is = 88%
Explanation:
conversion = 98% = 0.98
process rate = 0.03 m^3/s
length of reactor = 3 m
cross sectional area of reactor = 25 dm^2
pulse tracer test results on the reactor :
mean residence time ( tm) = 10 s and variance (∝2) = 65 s^2
note: space time (t) =
t = Vo = flow metric flow rate , L = length of reactor , A = cross sectional area of the reactor
therefore (t) = = 25 s
since the reaction is in first order
X = 1 -
= 1 - X
kt = In
k = In / t
X = 98% = 0.98 (conversion in PFR ) insert the value into the above equation then
K = 0.156
Calculating Da for a closed vessel
; Da = tk
= 25 * 0.156 = 3.9
calculate Peclet number Per using this equation
0.65 =
therefore
solving the Non-linear equation above( Per = 1.5 )
Attached is the Remaining part of the solution
