Carbon because they all have CHO in the chemical equations
The ideal gas under STP is 22.4 L/mol. While the gas has a rule of P1V1/T1=P2V2/T2. So the volume under 101 kPa and 273 K is 0.2*22.4=4.48 L.
Answer:
8.324 g
Explanation:
First we <u>convert 750.0 mL into L</u>:
- 750.0 mL / 1000 = 0.750 L
Then we <u>calculate the required number of moles of CaCl₂</u>, using the <em>definition of molarity</em>:
- Molarity = moles / liters
- Molarity * liters = moles
- 0.100 M * 0.750 L = 0.075 mol
Finally we <u>convert 0.075 moles of CaCl₂ into grams</u>, using its <em>molar mass</em>:
- 0.075 mol * 110.98 g/mol = 8.324 g
I think it's 6?...........
Answer:3.7427017316233497
Explanation:
