To make soemthing burn, bonds are broken to produce heat which is a change in chemical makeup
Answer:
Methanol is more acidic than the alkyne and will be deprotonated instead.
Explanation:
of methanol is around 15 and of terminal alkyne is around 26.
, where is acid dissociation constant
So, higher the acidity of an acid, higher will its value and thereby lower will be its value.
So, methanol is certainly stronger acid than terminal alkyne.
Hence sodium amide preferably deprotonates methanol instead of terminal alkyne.
Hence, option (A) is correct.
A: It creates a semi-permeable membrane that lets certain things in and keeps bad things out (large non polar stuff mostly with the exception of transport protiens) so protection
B, the physical components
Answer:
pH = 12.58
Explanation Careful
Since NaOH is a strong bond base you have to solve for pOH and then pH
pOH= 1.42
pH= 14-pOH
14-1.42= 12.58