Solve the problem. Express your answer to the correct number of significant figures

2) which statement describes ionic bonding?

garik1379 [7]

Answer

odpowiedzi d

Explanation

taka jest reguła

7 0

3 years ago

Hydrolamine ,NH2OH , is a reducing agent found in some film developing solutions. How many hydrogen atoms are in 1.80moles of hy

kolezko [41]

Answer:

number of hydrogen atom in 1.8 mole of NH2OH = $9.8\times 10^{22}$

Explanation:

percentage of hydrogen in NH2OH = mass of hydrogen / mass of whole molecule

= $\frac{3\times 1}{14+3+16}$ \times 100

= 9.09 percentage

therefore number of moles in 1.8 moles of hydroxy amine = $\frac{9.09}{100}\times 1.8$

= .16 moles of hydrogen

number of hydrogen atom = (number of moles )×(avagadro number)

= $9.8\times 10^{22}$ atoms of hydrogen

3 0

3 years ago

True or False, Atoms with fewer then 4 outer electrons lend electrons

hammer [34]

Answer:

true

I think please thanks

6 0

2 years ago

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At 850 K, the equilibrium constant for the reaction

Sphinxa [80]

Answer:

Answers are in the explanation.

Explanation:

Given concentrations are:

SO₂ = 0.20M O₂ = 0.60M SO₃ = 0.60M

SO₂ = 0.14M O₂ = 0.10M SO₃ = 0.40M

And SO₂ = 0.90M O₂ = 0.50M SO₃ = 0.10M

In the reaction:

2SO₂(g) + O₂(g) ⇄ 2SO₃(g)

Kc is defined as:

Kc = 15 = [SO₃]² / [O₂] [SO₂]²

Where concentrations of each species are equilbrium concentrations.

Also, you can define Q (Reaction quotient) as:

Q = [SO₃]² / [O₂] [SO₂]²

Where concentrations of each species are ACTUAL concentrations.

If Q > Kc, the reaction will shift to the left until Q = Kc;

If Q < Kc, the reaction will shift to the right until Q = Kc

If Q = Kc, there is no net reaction because reaction would be en equilibrium.

Replacing with given concentrations:

Q = [0.60M]² / [0.60M] [0.20M]² = 15; Q = Kc → No net reaction

Q = [0.40M]² / [0.10M] [0.14M]² = 82; Q > Kc, → Reaction will shift to the left

Q = [0.10M]² / [0.50M] [0.90M]² = 0.015; Q < Kc → Reaction will shift to the right

8 0

3 years ago

Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide. Ca) + H2O --> Ca(OH)2 In a particular

mars1129 [50]

Answer:

Percent yield = 92.5%

Explanation:

The question asks for the percent yield which can be defined as:

$\frac{actual yield}{theoretical yield} .100$

Where the actual yield is how much product was obtained, in this case 6.11 g of Ca(OH)₂, and the theoretical yield is how much product could be obtained with the given reactants theoretically, that is if the reaction would work perfectly. So we need to calculate first the theoretical yield.

1. First lets write the chemical equation reaction correctly and check that it is balanced:

CaO + H₂O → Ca(OH)₂

2. Calculate the amount of product Ca(OH)₂ that can be obtained with the given reactants (theoretical yield), which are 5.00g of CaO and excess of water. So the amount of CaO will determined how much Ca(OH)₂ we can obtained.

For this we'll use the molar ratio between CaO and Ca(OH)₂ which we see it is 1:1. For every mol of CaO we'll obtain a mol of Ca(OH)₂. So lets convert the 5.00 g of CaO to moles:

Molar Mass of CaO: 40.078 + 15.999 = 56.077 g/mol

moles of CaO = 5.00 g / 56.077 g/mol = 0.08916 moles

As we said before from the molar ratio moles of Ca(OH)₂ = moles of CaO

So the moles of Ca(OH)₂ that can be obtained are 56.077 g/mol

We need to convert this value to grams:

Molar Mass of Ca(OH)₂ = 40.078 + (15.999 + 1.008)*2 = 74.092 g/mol

Theoretical yield of Ca(OH)₂ = 0.08916 moles x 74.092 g/mol = 6.606 g

3. Calculate the percent yield:

$\frac{actual yield}{theoretical yield} .100$

Percent yield = (6.11 g / 6.606g) x 100 = 92.5 %

5 0

3 years ago

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