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Tema [17]
3 years ago
9

Soy flaco y largo, si tu en casa estás, mira en la puerta y me veras​

Physics
1 answer:
Vedmedyk [2.9K]3 years ago
7 0

Answer:

аалащщкдудуддкдкбдпаддужужуждк

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If a simple machine reduces the strength of a force, what must be increased?
uysha [10]

The distance that the force moves" is the one among the following choices given in the question that must be increased, if a simple machine reduces the strength of a force. The correct option among all the options that are given in the question is the first option or option. I hope the answer helped you.

6 0
3 years ago
To reduce auto emissions in the United States, modifications to automobile engines have been required since the 1960s.
natali 33 [55]

Answer:

True

Explanation:

8 0
2 years ago
One strategy in a snowball fight is to throw a snowball at a high angle over level ground. While your opponent is watching this
allsm [11]

Answer:

\theta_2 \approx 40.5^{\circ}

Explanation:

<u>Given:</u>

velocity of the ball first and ball second, v_1=v_2=v\,m.s^{-1}

angle of projection of the first ball, \theta_1= 72^{\circ}

∵The balls should land at the same point,

∴their range of projectile,

R_1=R_2=R\,m

As we know for the range of projectile:

R=\frac{v^2}{g}.sin\,2\theta

∵ we have equal range in both the cases

\therefore \frac{v_1^2}{g}.sin\,2\theta_1=\frac{v_2^2}{g}.sin\,2\theta_2

\Rightarrow \frac{v^2}{g}.sin\,(2\times 72) =\frac{v^2}{g}.sin\,2\theta_2

\Rightarrow sin 144^{\circ}=sin\,2\theta_2

2\theta_2=sin^{-1}[sin 144^{\circ}]

\theta_2=\frac{1}{2}\times sin^{-1}[sin 144^{\circ}]

\theta_2 \approx 40.5^{\circ}

8 0
3 years ago
What is the only "power" unit of measurement in light energy?
n200080 [17]
I believe it wattage or watts
8 0
3 years ago
Light traveling through air encounter a second medium which slows the light to 2.7 x 10^8. What is the index of the medium?
kozerog [31]

Answer:

1.11

Explanation:

The index of the medium can be calculated using below formula

V= c/ n ............eqn(1)

Where V= velocity of the light is reduced to while traveling through the second medium= 2.7 x 10^8 m/s

n= index of the medium

c= speed of light= 3 x 10^8 m/s

Substitute for the values in eqn(1)

2.7 x 10^8 = (3 x 10^8 m/s)/ n

Making " n" subject of the formula, we have

n= (3 x 10^8 )/(2.7 x 10^8)

n= 1.11

Hence, the index of the medium is 1.11

5 0
3 years ago
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