Sand. sand is much lighter and can be carried further
Answer:
x = 0.67 m
Explanation:
For this problem, let's use the projectile launch equations, as the jug goes through the bar, it comes out with horizontal speed vx = 1.3 m / s, which does not decrease as there is no friction.
Let's find the time or it takes to get to the floor
y = y₀ + v_{oy} - ½ g t²
in this case I go = 0 and when I get to the floor y = 0
0 = y₀ + 0 - ½ g t²
t² = 2y₀ / g
t² = 2 1.3 / 9.8 = 0.2653
t = 0.515 s
now let's find the distance traveled in this time
x = vx t
x = 1.3 0.515
x = 0.6696 m
x = 0.67 m
Explanation:
Momentum is conserved:
m₁v₁ = m₂v₂
(42.8 kg + 31.5 kg + 25.9 kg) (19.8 m/s) = (31.5 kg + 25.9 kg) v
v = 34.6 m/s
Answer:
Explanation:
Work is the product of force and distance, so the formula is:
The work is 6.00 Joules, but
- 1 Joule (J) is equal to 1 Newton meter (N*m).
- Therefore, the work of 6.00 J is equal to 6.00 N*m
The force is 2.50 Newtons.
The known values are:
Substitute the values into the formula.
We are solving for distance, so we must isolate the variable, d. It is being multiplied by 2.50 Newtons and the inverse of multiplication is division. Divide both sides by 2.50 N.
The units of Newtons cancel out.
The force was applied to the rock over a distance of <u>2.40 meters</u> and choice <u>C</u> is correct.
<span>LAWS OF MOTION:
The motion of an object parallel to the earth's surface is: Horizontal </span>