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RideAnS [48]
3 years ago
9

Define light year and explain how and why light years are used to measure distances in the universe

Physics
1 answer:
Mashcka [7]3 years ago
5 0
Distances ANYWHERE could be described in terms of inches, feet,
yards, miles, kilometers, nanometers, centimeters, millimeters, or
even AU (Astronomical Units).  But if you tried to use any of these
to describe the distance of anything away from the Earth's surface, 
you'd be faced with a ridiculous number.  It would be very hard to
remember this number or tell other people about it, and impractical
to write this number down in your notebook.

For example: The average distance between Earth and the moon is

38,440,145,820 centimeters,

and the distance to the nearest star outside the solar system
is approximately

1,671,433,491,000 kilometers.

Isn't that ridiculous ! ?

Obviously, we need much bigger units to describe these distances,
so that we can talk about them in more convenient numbers.  so the
light year was invented to fill this need.  It's simply the distance that
light travels through vacuum in one year.

Definition of 1 light year = exactly 9,460,730,472,580,<span>800 meters
</span>
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1) For a positive point charge, the lines radiate ………. . While, for a negative point charge, the lines converge …………. .
ch4aika [34]

Answer:

For a positive point charge, the lines radiate <u>outwards</u>, while for a negative point charge, the lines converge<u> inwards.</u>

Explanation:

A single point charges produces an electric field which has a radial shape.The sign of a charge determines the the direction of the field. In Positive charge have the direction of field is out of the charge and for negative charge, the direction of field is towards the charge.This behavior is in relation to how a positive test charge will experience in a field.

5 0
3 years ago
If you free the cork in a highly pressurized champagne bottle, the resulting launch of the cork will, in principle, cause the bo
Rudiy27

Answer:

6.7 × 10^{-2}

Explanation:

Initial P = Final P

(1.8 × 0) + (.0075 × 0) = (1.8 × x) + (.0075 × 16)

-.12 + 1.8x

x = .0067

5 0
3 years ago
Lithium is more active than aluminium<br> A.True<br> B.false
WITCHER [35]
A:True because Lithium is the lighest solid and metal and the third lightest element.
5 0
3 years ago
Read 2 more answers
A 230-km-long high-voltage transmission line 2.0 cm in diameter carries a steady current of 1,100 A. If the conductor is copper
Molodets [167]

Answer:

28.23 years

Explanation:

I = 1100 A

L = 230 km = 230, 000 m

diameter = 2 cm

radius, r = 1 cm = 0.01 m

Area, A = 3.14 x 0.01 x 0.01 = 3.14 x 10^-4 m^2

n = 8.5 x 10^28 per cubic metre

Use the relation

I = n e A vd

vd = I / n e A

vd = 1100 / (8.5 x 10^28 x 1.6 x 10^-19 x 3.14 x 10^-4)

vd = 2.58 x 10^-4 m/s

Let time taken is t.

Distance = velocity x time

t = distance / velocity = L / vd

t = 230000 / (2.58 x 10^-4) = 8.91 x 10^8 second

t = 28.23 years

5 0
4 years ago
Read 2 more answers
You drag a crate across a floor with a rope. The force applied is 750 N and the angle of the rope is 25.0° above the horizontalH
frez [133]

a.

The work done by a constant force along a rectilinear motion when the force and the displacement vector are not colinear is given by:

W=F\cos\theta\cdot d

where F is the magnitude of the force, theta is the angle between them and d is the distance.

The problen gives the following data:

The magnitude of the force 750 N.

The angle between the force and the displacement which is 25°

The distance, 26 m.

Plugging this in the formula we have:

\begin{gathered} W=\left(750\right)\left(\cos25\right)\left(26\right) \\ W=17673 \end{gathered}

Therefore the work done is 17673 J.

b)

The power is given by:

P=\frac{W}{t}

the problem states that the time it takes is 6 s. Then:

\begin{gathered} P=\frac{17673}{6} \\ P=2945.5 \end{gathered}

Therefore the power is 2945.5 W

5 0
1 year ago
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