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Valentin [98]
2 years ago
15

What is Multimeter?Thenku!!​

Physics
2 answers:
Nesterboy [21]2 years ago
8 0

Answer:

an instrument designed to measure electric current, voltage, and usually resistance, typically over several ranges of value.

larisa [96]2 years ago
3 0

Answer:

A multimeter is a measuring instrument that can measure multiple electrical properties. A typical multimeter can measure voltage, resistance, and current, in which case it is also known as a volt-ohm-milliammeter, as the unit is equipped with voltmeter, ammeter, and ohmmeter functionality

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What force does it take to accelerate a 7.2 kg object 3.0 m/s^2.
grin007 [14]

Answer:

<h2>21.6 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 7.2 × 3 = 21.6

We have the final answer as

<h3>21.6 N</h3>

Hope this helps you

3 0
2 years ago
Diffraction occurs when waves _____ after passing through an opening
saw5 [17]
The answer to your question is A
8 0
4 years ago
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HELP PLEAASE!!!You push against a steamer trunk with a force of 750 N at an angle of 25° with the horizontal . The trunk is on a
viva [34]
<span>your answer is m = 59 kg</span>
5 0
3 years ago
a swimmer can swim in still water at a speed of 9.50 m/s. he intends to swim directly across the river that has a downstream cur
Doss [256]
Refer to the diagram shown below.

Still-water speed  = 9.5 m/s
River speed = 3.75 m/s down stream.

The velocity of the swimmer relative to the bank is the vector sum of his still-water speed and the speed of the river.

The velocity relative to the bank is
V = √(9.5² + 3.75²) = 10.21 m/s

The downstream angle is
θ = tan⁻¹ 3.75/9.5 = 21.5°

Answer:  10.2 m/s at 21.5° downstream.

7 0
4 years ago
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A person hears a siren as a fire truck approaches and passes by. The frequency varies from 480Hz on approach to 400Hz going away
alekssr [168]

Answer:

31.2 m/s

Explanation:

f_{app} = Frequency of approach = 480 Hz

f_{aw} = Frequency of going away = 400 Hz

V = Speed of sound in air = 343 m/s

v = Speed of truck

Frequency of approach is given as

f_{app} = \frac{Vf}{V - v}                           eq-1

Frequency of moving awayy is given as

f_{aw} = \frac{Vf}{V + v}                          eq-2

Dividing eq-1 by eq-2

\frac{f_{app}}{f_{aw}} = \frac{V + v}{V - v}

\frac{480}{400} = \frac{343 + v}{343 - v}

v = 31.2 m/s

7 0
3 years ago
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