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amid [387]
2 years ago
13

2. Circle all of the following that change with the temperature of a reaction.

Chemistry
1 answer:
sergey [27]2 years ago
6 0

The activation energy (Ea)  for the reaction is calculated from the slope as is - 1.16kJ.

<h3>What the Arrhenius equation?</h3>

The Arrhenius equation relates the rate constant of a reaction to the temperature of the reaction. It is an offshoot of the collision theory. We must note that the collision factor A is the y intercept of the graph.

Given that T = -350 K

R = 8.314 J/K.mol

Ea = ??

-350 = Ea/8.314

Ea = -350 × 8.314

Ea = - 1.16kJ

Learn more about activation energy:brainly.com/question/11334504

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A chemist pours 1 mol of zinc granules into one beaker and 1 mol of zinc chloride powder into another beaker. What do the two sa
Oksana_A [137]
Answer is: <span> two samples have in common same amount of substance and same number of particles.
1) There are same amount of substance in both beakers:
n(Zn) = 1 mol.
n(ZnCl</span>₂) = 1 mol.
2) There are same number of particles (atoms, molecules, ions) in both beakers:
N(Zn) = n(Zn) · Na.
N(Zn) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ atoms of zinc.
N(ZnCl₂) = n(ZnCl₂) · Na.
N(ZnCl₂) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ molecules of zinc(II) chloride.
Na - Avogadro number.


5 0
3 years ago
Read 2 more answers
This application demonstrates how an understanding of free energy can explain seemingly unfavorable reactions proceeding, seemin
azamat

Answer: your question is incomplete, please let me assume this to be your question.

This application demonstrates how an understanding of free energy can explain seemingly unfavorable reactions proceeding, seemingly, spontaneously. Glycolysis is the process by which energy is harvested from glucose by living things. Several of the reactions of glycolysis are thermodynamically unfavorable (nonspontaneous), but proceed when they are coupled with other reactions.

ReactionA: P i + glucose ⟶ glucose-6-phosphate + H 2 O Δ G = 13.8 kJ / mol Reaction

ReactionB: P i + fructose-6-phosphate ⟶ fructose-1,6-bisphosphate + H 2 O Δ G = 16.3 kJ / mol

Reaction C: ATP + H 2 O ⟶ ADP + P i Δ G = − 30.5 kJ / mol

1. Which of these reactions is (are) unfavorable? Select all that apply.

2. Which of these reactions can be coupled so that overall reaction is favorable? Select all that apply.

3. What is the net change in free energy if one selection from part (b) is coupled so that the overall reaction is favorable?

THE ANSWERS ARE AS FOLLOWS

1. REACTION B IS UNFAVOURABLE

2. REACTION A AND C CAN BE COUPLED SO THAT OVERALL REACTION IS FAVOURABLE

3. Since reaction b is coupled the net change becomes

13.8+16.3= 30.1

Therefore the net free change becomes

30.5 - 30.1 = 0.4kj/mol

Explanation: The glycolysis pathway

is to describe the oxidation of glucose to pyruvate, with the generation of ATP and NADH. This pathway is also known as the EMBDEN-MEYERHOF PATHWAY.

Reaction B is unfavorable because it is the conversation of glucose into an unstable form, that can be readily cleaved into 3-carbon units. The unfavorable fructose-6-phosphate is quickly consumed to favour the forward reaction.

Reaction A and Reaction C makes the overall reaction to be favoured, since the unfavorable reaction is reaction B, which is an intermediate reaction.

In calculation of net free energy the negative sign which shows Exothermic reaction is multiplied by a negative sign.

The final energy minus the initial energy. The reaction B is added to the initial energy because it is an intermediate reaction, and we were told that one part of it is coupled to the reaction.

Hope this has helped you to solve your question.

5 0
4 years ago
Find the number of chromium ions in 3.5 mol of chromium ions.
Ray Of Light [21]

Answer:

2.1 x 10^24 Cr ions

Explanation:

You  need to multiply the 3.5 mol by the Avogrado's number (6.022 x 10^23) to get your answer.

3 0
3 years ago
What is the correctly balanced chemical equation for the reaction of KOH and H2SO4
True [87]

KOH + H2SO4 —> K(+) + HSO4(-) + H2O

Or a total reaction

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4 0
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Semmy [17]

Answer: An object has a weight of 10 kg on the surface of Earth. If the same object were transported to the surface of Mars, the object would have a weight of 3.8 kg. The density of the object is greater on Earth than it is on Mars.

Explanation:

6 0
3 years ago
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