From ideal gas equation PV = nRT, V/T = nR/P ==> V/T = constant. Therefore V1/T1 = V2/T2 ==> 7.8/698 = V2/308. V = 3.44L {TEMPERATURE IN KELVIN = 273 + 425 AND 35 = 698 AND 308}
The answer is B: chronological order
a. AgBr(s)⇒ Ag⁺(aq) + Br⁻(aq)
b. Ksp AgBr = s²
c. 5 x 10⁻¹³ mol/L
<h3>Further explanation</h3>
Given
solubility AgBr = 7.07 x 10⁻⁷ mol/L
Required
The dissolution reaction
Ksp
The solubility product constant
Solution
a. dissolution reaction of AgBr
AgBr(s)⇒ Ag⁺(aq) + Br⁻(aq)
b. Ksp
Ksp AgBr = [Ag⁺] [Br⁻]
Ksp AgBr = (s) (s)
Ksp AgBr = s²
c. Ksp AgBr = (7.07 x 10⁻⁷)² = 5 x 10⁻¹³ mol/L
It would move due to it not being<span> the same speed and in the same direction so it is acted upon by an unbalanced force.</span>
Answer:
The answer is B, Alanine would be in the interior and serine would be on the exterior of the globular protein.
Explanation:
To further explain, the nature of solubility of side chain determines the position of the amino acid in the globular protein.
The hydrophilic amino acid such as serine are on the outside of the globular protein while the hydrophic amino acids such as leucine and alanine are on the interior of the globular protein.
This is why Alanine would be in the interior and serine would be on the exterior of the globular protein.
Cheers!
