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Mandarinka [93]
2 years ago
15

Most scientists, inventors and engineers do not come up with their ideas all on their own but rather

Physics
1 answer:
Natalka [10]2 years ago
6 0

Answer:

Benjamin Franklin, Thomas Edison

and Robert Anderson, Thomas Davenport

Explanation:

Edison was Franklin's idol in studying electricity (Edison's electric light bulb, and Franklin's metal key string kite static experiment)

Anderson and Davenport for the first electric car

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A 0.150 kg baseball has 118 j of KE. how fast is the ball moving?(unit=m/s)
MrRissso [65]

Answer:

Explanation 118 = (1/2) * 0.15 * v² 118 = 0.075 * v² v² = 1573.33 m/s ... since KE = m/2*V^2 , then : V = √2KE/m = √20*118/1.5 = 39.67 m//sec ( 142.8 km/h ; 88.75 mph).:

4 0
3 years ago
An electron and a proton have the same kinetic energy upon entering a region of constant magnetic field and their velocity vecto
kupik [55]

Answer: rp/re= me/mp= 544 * 10^-6.

Explanation: To calculate this problem we have to consider the circular movement by the electron and proton inside a magnetic field.

Then the dynamic equation for the circular movement is given by:

Fcentripetal= m*ω^2.r

q*v*B=m*ω^2.r

we write this for each particle then we have the following:

q*v*B=me* ω^2*re

q*v*B=mp* ω^2*rp

rp/re=me/mp=9.1*10^-31/1.67*10^-27=544*10^-6

4 0
3 years ago
Static electricity is the study of?
Elanso [62]
The study of static electricity is electrostatics
4 0
3 years ago
Consider a string with a length of (47.5 A) cm tied at both end (like on a stringed instrument). If the frequency of the first h
zubka84 [21]

To solve this problem it is necessary to apply the concepts related to wavelength as a function of frequency and speed, as well as to determine the wavelength as a function of length.

From the harmonic vibration generated we know that the total length of the string will be equivalent to a half of the wavelength, that is

L = \frac{\lambda}{2} \rightarrow \lambda = 2L

Where,

\lambda = Wavelength

Therefore the wavelength for us would be,

\lambda = 2*47.5cm = 95cm = 0.95m

From the relationship of speed, frequency and wavelength we know that

\lambda = \frac{v}{f} \rightarrow v = \lambda f

v = (0.95m)(245Hz)

v = 232.75 m/s

Therefore the speed of the wave is 232.75m/s

4 0
3 years ago
NASA communicates with the Space Shuttle and International Space Station using Ku-band microwave radio. Suppose NASA transmits a
jeyben [28]

Answer:

λ₁ = 2.50 10⁻² m,   λ₂ = 1.66 10⁻² m  

Explanation:

Microwave communication is very efficient because it does not have atmospheric interference, for which it is widely used and has been regulated to avoid interference, the ku band is in the range between 12 and 18 GHz.

Let's calculate the wavelength for the two extreme frequencies of this band

wavelength and frequency are related

         c = λ f

          λ = c / f

f₁ = 12 GHz = 12 10⁹ Hz

          λ₁ = 3 10⁸ /12 10⁹

           λ₁ = 2.50 10⁻² m

f₂ = 18 GHz = 18 10⁹ Hz

          λ₂ = 3 10⁸ /18 10⁹

          λ₂ = 1.66 10⁻² m

Unfortunately in your exercise the specific frequency is not fired, for significant figures they must be the same number as the figures of the frequency, in general the frequency has 3 or 4 significant figures

8 0
3 years ago
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