Answer:

Explanation:
We are given that


d=1.9 cm=
Using 1m=100 cm
We have to find the electric field strength.

Using the formula





Mass of electron,m

Substitute the values


Icecaps that are dissolving, a system of canal-like geometric features, and various pitch black surface markings are all thought to be vegetation are the observations of the martian surface led Lowell to the conclusion that intelligent life forms existed on Mars.
<h3>What is a solar system?</h3>
It is a system that collection of all the planets and spatial bodies revolving around the sun because of the gravitational pull of the sun.
Our Solar System is based on a heliocentric model in which the Sun is assumed to reside at the central point of the planetary system.
In other words, the Sun is at the center while the Earth and other planetary bodies revolve around it.
Lowell came to the conclusion that intelligent life existed on Mars based on his observations of the martian surface, which included melting icecaps, a network of geometric patterns that resemble canals, and numerous markings on the completely black surface that are believed to be flora.
Learn more about Solar systems from here,
brainly.com/question/12075871
#SPJ4
Answer:
ooh thanks but don't give me advise
50 +50 =100 Since it’s sitting on a 50m cliff that’s high with a mass of 50 kg it would be adding because once it goes down it’s adding speed
I think you go to my school!