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irinina [24]
2 years ago
12

Devon is riding his bicycle at 15 m/s. How far will he travel in 12 s?

Physics
1 answer:
Gre4nikov [31]2 years ago
6 0
Devon will travel 180m in 12 seconds. All you have to do is multiply 15 by 12. Hope this helps
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A ball tossed vertically upward from the ground next to a building passes the bottom of a window 1.8 s after being tossed and pa
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The ball takes 0.2 sec to travel the height of the window, which is 2 m.

 Then the speed of the ball at that time was

v = \frac{d}{t}

v = \frac{2}{0.20}

v = 10\ \frac{m}{s}

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v = v_0 -gt

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So:

10 = v_0 -9.8(2)

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v_0 = 29.6\ m / s

Then we have the equation for the position as a function of time.

r = r_0 + v_0t - \frac{1}{2}gt^2

Where

r_0 = initial position

r = position as a function of time

v_0 = initial velocity

g = acceleration of gravity

t = time.

If the ball is thrown from the ground then:

r_0 = 0 m

We want to find now the distance between the window and the ground.

When the ball reaches the bottom of the window t = 1.8s

So:

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The window is 37,404 m high

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v = v_0 -gt\\\\0 = v_0 -gt\\\\gt = v_0\\\\t = \frac{29.6}{9.8}

t = 3.02\ s

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3 0
3 years ago
A student decides to give his bicycle a tune up. He flips it upside down (so there's no friction with the ground) and applies a
aleksklad [387]

Answer:

V=9.2565m/s

Explanation:

From the question we are told that:

Force F = 34 N  

Time t = 0.6 s

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Radius of wheel r = 33 cm = 0.33 m

Moment of inertia, I = 1200 kgcm2 = 0.12 kg.m2

Generally the equation for Torque on pedal \mu is mathematically given by

\mu=F*L\\\mu=34*0.165

\mu=5.61N.m

Generally the equation for  angular acceleration \alpha is mathematically given by

 \alpha=\frac{\mu}{l}

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Therefore Angular speed is \omega

\omega=\alpha*t

\omega=(46.75)*(0.6)

\omega=28.05rad/s

Generally the equation for  Tangential velocity V is mathematically given by

V=r\omega

V=(0.33)(28.05)

V=9.2565m/s

 

5 0
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