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oksano4ka [1.4K]
3 years ago
13

While doing a lab, a student found the density of a piece of pure aluminum to be 2.85 g/cm3. The accepted value for the density

of aluminum is 2.70 g/cm3. What was the student's percent error?
Physics
1 answer:
bezimeni [28]3 years ago
3 0
The equation for percent error is

% Error = 100*|Experimental-Theoretical|/Theoretical

Our experimental is 2.85g/cm^3 and the accepted is 2.7g/cm^3

Thus our % Error = 5.555%
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This is a question that would have literally have taken two seconds to look up on google but the answer is 1.88 years.

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Anna Litical analyzes the force between a planet and its moon, varying the mass of
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Trial 1 is the largest, trial 3 is the smallest

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<em>Trial 1</em>

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<em>Trial  2</em>

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<em>Trial  3</em>

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___________

F - ?

Gravitational force:

F₁ = G·m·M₁ / d₁² = m·6.67·10⁻¹¹·6·10²² / (3.5·10⁶)² = 0.37·m  (N)

F₂ = G·m·M₂ / d₂² = m·6.67·10⁻¹¹·6·10²² / (7·10⁶)² = 0.08·m  (N)

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5 0
1 year ago
9. How much energy does a 100 W light bulb use in half an hour? If the light bulb converts
yulyashka [42]

The energy used by the light bulb in half an hour is 180000 J and the amount of thermal energy generated is 158400 J.

What is Energy?

Energy is the ability or the capacity to do work.

To calculate the energy of the light bulb we use the formula below

Formula:

  • E = Pt.......... Equation 1

Where:

  • E = Energy used by the bulb in a half-hour
  • P = Power of the bulb
  • t = Time

Given:

  • P = 100 W
  • t = 1/2 hour = 30 minutes = (30×60) = 1800 seconds

Substitute these values into equation 1

  • E = (100×1800)
  • E = 180000 J

  • If the light converts 12% of electric energy to light energy, then  88% of the energy is used to generate thermal energy

Therefore,

  • Thermal energy = (180000×88/100) = 158400 J

Hence, the energy used by the light bulb in half an hour is 180000 J and the amount of thermal energy generated is 158400 J.

Learn more about energy here: brainly.com/question/21927255

#SPJ1

6 0
2 years ago
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