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4 years ago

5

1.Which gas law uses only variables to find a missing variable?

1 answer:

DanielleElmas [232]4 years ago

5 0

1). D. Combined Gas Law
3.) D. Pressure and temperature
4.) C. Boyles law

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A car travelling at 30 mph takes 10 m to come to a complete stop. Consider the work done by the brakes when stopping to estimate

vodka [1.7K]

Answer:

The value of the distance S = 62.5 m

Explanation:

From third law of motion

$v^{2} = u^{2} + 2 as\\$

v = 0 & u = 30

So 0 = $30^{2}$ + 2 × a × 10

a = - 45 $\frac{m}{s^{2} }$

When the car speed is 75 $\frac{mi}{hr}$ then in that case

u = 75 $\frac{mi}{hr}$ , v = 0

$v^{2} = u^{2} + 2 as\\$

$75^{2} = - 2 a S$

$S = \frac{75^{2} }{-2 (-45)}$

S = 62.5 m

This is the value of the distance.

7 0

3 years ago

Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1200 kg and was approaching at

igomit [66]

To resolve point A and B we need the concepts related to conservation of momentum (By collision) and Kinetic Energy. Conservation of momentum is given by the equation,

$m_1\vec{v_1}+m_2\vec{v_2} = (m_1+m_2)\vec{v}$

Our values in the statment are:

$m_1 = 1200kg$

$v_1 = 6m/s$

$m_2 = 900kg$

$v_2 = 24m/s$

Part A) As it is in an icy intersection, there is two different components (x,y) then,

$1200(-6\hat{j})+900(-24\hat{i}) = (1200+900)\vec{v}$

$2100\vec{v} = -21600\hat{i}-7200\hat{j}$

$\vec{v} = -72/7\hat{i}-24/7\hat{j}$

Then the magnitude is,

$|\vec{v}| = 9.6525m/s$

Part B) To obtain the Kinetic Energy Loss we need to use its equation, which is given by,

$KE_i = \frac{1}{2}m_1v_1^2+\frac{1}{2}m_2v_2^2$

$KE_i = \frac{1}{2}(1200)(6)^2+\frac{1}{2}(900)(24)^2$

$KE_i = 280.8kJ$

The final energy is given by,

$KE_f = \frac{1}{2}(m_1+m_2)v_f^2$

$KE_f = \frac{1}{2} (1200+900)(9.65)$

$KE_f =97778.625J$

Then the change in Kinetic Energy is

$\Delta KE = KE_f-KE_i = 97.778kJ- 280.8kJ$

$\Delta KE = -183.02kJ$

<em>There was a loss of KE of 183.02kJ</em>

5 0

4 years ago

Your parents order an oven from England. The temperature dial on the new oven is calibrated in degrees

Anuta_ua [19.1K]

You need to remember this equation:

<span>Fahrenheit = (Celsius * 9/5) + 32
</span>-->662
(Please double check this though)

5 0

3 years ago

An object is placed 110 mm from a concave mirror with a focal length of 5.0 cm.

Nady [450]

Answer:

Approximately 92 mm.

Explanation:

Object's distance, u = 110 mm = 11 cm

focal length of the mirror = 5 cm

Image distance, v = ?

To determine the image distance, apply the mirror's formula;

$\frac{1}{f}$ = $\frac{1}{u}$ + $\frac{1}{v}$

$\frac{1}{v}$ = $\frac{1}{f}$ - $\frac{1}{u}$

= $\frac{1}{5}$ - $\frac{1}{11}$

= $\frac{11-5}{55}$

$\frac{1}{v}$ = $\frac{6}{55}$

⇒ v = $\frac{55}{6}$

= 9.166667

v = 9.2 cm

The image distance is 92 mm.

7 0

3 years ago

Question 1 of 10

ivanzaharov [21]

The answer would be 46.482 because you multiply 18.3 by 2.54 because for every inch you get 2.54 centimeters

6 0

2 years ago

Read 2 more answers