Answer:
2L of water.
Explanation:
To know the volume of water to be added to the initial solution, first let us calculate the volume of the final solution. This is illustrated below:
Data obtained from the question:
Initial volume (V1) = 2L
Initial concentration (C1) = 6mol/L
Final concentration (C2) = 3mol/L
Final volume (V2) =?
Using the dilution formula, we can obtain the final volume of the stock as follow:
C1V1 =C2V2
6 x 2 = 3 x V2
Divide both side by 3
V2 = (6 x 2)/3
V2 = 4L.
The final volume of the solution is 4L.
To obtain the volume of water added, we shall determine the change in the volume of the solution. This is illustrated below:
Initial volume (V1) = 2L
Final volume (V2) = 4L
Change in volume = V2 – V1 = 4 – 2 = 2L.
Therefore, 2L of water must be added to the initial solution.
Answer:
Please mark me brainliest. the answer is
Explanation:
The problem is that the desalination of water requires a lot of energy. Salt dissolves very easily in water, forming strong chemical bonds, and those bonds are difficult to break. Energy and the technology to desalinate water are both expensive, and this means that desalinating water can be pretty costly.
The molecular geometry is trigonal planar. I would choose E
In the lake that the rivers lead, water molecules evaporate into the sky and form clouds. In the sky, these water droplets condense and form clouds that will eventually rain.
I believe the problem is just simply asking for us to convert the value from one unit to the other. This case from m^3 to km^3. From the SI units, we know 1 km is equal to 1000 m. We do as follows:
118 m^3 ( 1 km / 1000 m )^3 = 1.18 x 10^-7 km^3
