A. sodium and chlorine b. carbon and hydrogen c. nitrogen and hydrogen d. bromine
B) 1.50 mol
Since O2 and H2O are in a 1:2 ratio, multiply 0.75×2 = 1.50
Atomic mass / mass number / atomic weight
(all of which mean the same thing)
Answer:
2L of nitrogen gas will be needed
Explanation:
Based on the following reaction:
N₂ + 3H₂ → 2NH₃
<em>1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.</em>
<em />
If 6L of hydrogen (In a gas, the volume is directly proportional to the moles, Avogadro's law) react, the volume of nitrogen gas required will be:
6L H₂ * (1mol N₂ / 3 moles H₂) =
<h3>2L of nitrogen gas will be needed</h3>
