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kupik [55]
3 years ago
7

Which descriptions apply to emitted radiation? Check all that apply. measurement in Ci/Bq measurement in conventional rad or the

SI Gy the amount of radioactive materials released into the environment. number of disintegrations of radioactive atoms in a radioactive material over a period of time absorbed dose (the amount of energy deposited per unit of mass of human tissue)
Chemistry
2 answers:
xxTIMURxx [149]3 years ago
7 0
The correct answer is measurement in Ci/Bq, the amount of radioactive materials released into the environment, and <span>number of disintegrations of radioactive atoms in a radioactive material over a period of time. I hope this helps.</span>
Llana [10]3 years ago
6 0

Answer:

- Measurement in Ci/Bq

- The amount of radioactive materials released into the environment.

- Number of disintegrations of radioactive atoms in a radioactive material over a period of time.

Explanation:

Hello,

In this case, the following options are valid:

- Measurement in Ci/Bq : one becquerel is understood as the quantity of a radioactive element in which there is one atomic disintegration per second.

- The amount of radioactive materials released into the environment: this technique is suitable to compute the amount of radioactive materials that are being or were released to the environment.

- Number of disintegrations of radioactive atoms in a radioactive material over a period of time: this technique provides becquerel which were described on the first option.

Best regards.

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Part b select the ester that is formed when propanoic acid reacts with isopropyl alcohol in the presence of heat and an acid cat
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<span>The ester that is formed by combining propanioc acid with isopropyl alcohol, using heat and an acid catalyst is isopropyl propanoate.</span>
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3 years ago
Calculate the amount of heat needed to melt 99.9 g of solid acetic acid (HCH,CO2) and bring it to a temperature of 85.1 °C. Roun
Nadusha1986 [10]

Q = 1.161 J/kg of heat is required to melt 99.9 g of solid acetic acid (HCH,CO2). Q = mL(Latent heat is the energy emitted or absorbed by a body while changing it state ). (Latent heat is the energy released or absorbed by a body while changing it state ).

<h3>How to fix?</h3>

Apply the equation Q = mL where:

Energy is Q. (J)

m = Mass (g)

L = Acetic acid's latent heat of fusion 192(J/g) = J/g

Q is equal to 0.099 kg times 11.73 kj/mol.

Q = 1.161J/kg.

<h3>What is latent heat, and what varieties are there?</h3>

Latent heat is the amount of energy that a substance experiencing a change in state, such as ice turning into water or water turning into steam, can absorb or release while maintaining a constant temperature and pressure. Types: The material exists in three states: solid, liquid, and gaseous.

<h3>What does "sensible heat" mean?</h3>

Heat that can actually be felt is considered to be sensible heat. Instead of the phase shifting, energy is what causes the temperature to vary as it moves from one system to another. For instance, it warms the water instead of melting the ice.

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3 0
1 year ago
The pressure exerted by 1.5 mol of gas in a 13 L flask at 22 °C is ____ kPa
sukhopar [10]

Answer:

282.7KPa

Explanation:

Step 1:

Data obtained from the question.

Number of mole of (n) = 1.5 mole

Volume (V) = 13L

Temperature (T) = 22°C = 22 + 273°C = 295K

Pressure (P) =..?

Gas constant (R) = 0.082atm.L/Kmol

Step 2:

Determination of the pressure exerted by the gas.

This can be obtained by using the ideal gas equation as follow:

PV = nRT

P = nRT /V

P = 1.5 x 0.082 x 295 / 13

P = 2.79atm.

Step 3:

Conversion of 2.79atm to KPa.

This is illustrated below:

1 atm = 101.325KPa

Therefore, 2.79atm = 2.79 x 101.325 = 282.7KPa

Therefore, the pressure exerted by the gas in KPa is 282.7KPa

8 0
3 years ago
As an EPA scientist studying catalytic converters and urban smog, you want to find Kc for the following reaction: 2NO2(g) ⇋ N2(g
Bas_tet [7]

Answer:

Kc = 4.774 * 10¹³

Explanation:

the desired reaction is

2 NO₂(g) ⇋ N₂(g) + 2 O₂(g)

Kc =[N₂]*[O₂]² /[NO₂]²

Since

1/2 N₂(g) + 1/2 O₂(g) ⇋ NO(g)

Kc₁= [NO]/(√[N₂]√[O₂]) →  Kc₁²= [NO]²/([N₂][O₂])

and

2 NO₂(g) ⇋ 2 NO(g) + O₂(g)

Kc₂= [NO]²*[O₂]/[NO₂]² →  1/Kc₂= [NO₂]²/([NO]²[O₂])

then

Kc₁²* (1/Kc₂) = [NO]²/([N₂]*[O₂]) *[NO₂]²/([NO]²[O₂])  = [NO₂]²/([N₂]*[O₂]²) = 1/Kc

Kc₁² /Kc₂ = 1/Kc

Kc= Kc₂/Kc₁² =1.1*10⁻⁵/(4.8*10⁻¹⁰)² = 4.774 * 10¹³

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