Ase/xual reproduction is not a good option for a large population because of what? /

2. Which of the following expressions is generally used for solubility? (1 point)

miskamm [114]

Answer:

For 2: The correct answer is grams of solute per 100 grams of solvent.

For 3: The correct answer is supersaturated.

For 4: the correct answer is the solubility decreases.

Explanation:

For 2:

Solubility is defined as the property which refers to the ability of the solute that can be dissolved in a solvent. It is defined as the number of grams of solute per 100 grams of solvent.

For 3:

Unsaturated solution is defined as the solution in which amount of solute that is dissolved in the solvent is less.

Saturated solution is defined as the solution in which no more solute can be dissolved in the given amount of solvent.

Emulsion is defined as the dispersion of one liquid in another liquid in which it is not soluble.

Supersaturated solution is defined as the solution in which solvent contains more amount of solute than the required amount. These solutions help in the process of crystallization.

When a crystal is added to a supersaturated solution, more and more particles come out of the solution and this process is known as crystallization.

For 4:

According to the Henry's Law

The solubility of the gas in a liquid is directly proportional to the partial pressure of the gas.

$\text{Solubility of a gas in a liquid}\propto \text{Partial pressure of the gas}$

With increase in the partial pressure, the solubility of the gas in liquid also increases and vice-versa.

Hence, the correct answer is the solubility decreases.

7 0

3 years ago

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the pressure and temperature of 10 liters of gas are doubled. if the original condition are 2 atmosphere of pressure and 400k wh

Harman [31]

Answer:

$\boxed{\text{10 L}}$

Explanation:

We have two pressures, two temperatures, and one volume.

This looks like a question in which we can use the Combined Gas Law to calculate the volume.

$\dfrac{p_{1}V_{1}}{T_{1}} = \dfrac{p_{2}V_{2} }{T_{2}}$

Data:

$\begin{array}{rclrclrcl}p_{1}& =& \text{2 atm}\qquad & V_{1} &= & \text{10 L}\qquad & T_{2}& =& \text{400 K}\\p_{2}& =& \text{4 atm}\qquad & V_{2} &= & \text{?}\qquad & T_{2}& =& \text{800 K}\\\end{array}$

Calculation:

$\begin{array}{rcl}\dfrac{2 \times 10}{400}& =& \dfrac{4V_{2} }{800}\\\\0.050& = &0.0050V_{2}\\V_{2}& = &\mathbf{10 L}\end{array}\\\text{The final volume is }\boxed{\textbf{10 L}}$

4 0

3 years ago

How much ch2o is needed to prepare 445 ml of a 2.65 m solution of ch2o?

worty [1.4K]

Answer: 35.4 grams

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

Molality = 2.65

n= moles of solute =?

$V_s$ = volume of solution in ml = 445 ml

Putting in the values we get:

$2.65=\frac{n\times 1000}{445ml}$

$n=1.18$

Mass of solute in g= $moles\times {\text {molar mass}}=1.18mol\times 30.02g/mol=35.4g$

Thus 35.4 grams of $CH_2O$ is needed to prepare 445 ml of a 2.65 m solution of $CH_2O$ .

8 0

3 years ago

An atom has 5 protons, 4 electrons, and 5 neutrons. Which

Likurg_2 [28]

Answer:

i think the answer is C

Explanation:

not sure plsss dont bash im a beginner

3 0

3 years ago

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A student explained to the class that helium has 8 valence electrons because it is in group 18. Is the student correct?

lys-0071 [83]

The student is incorrect because helium has 2 valence electrons and it's in group 18 because the first energy level is full. Although helium is placed in Group 18 which generally has 8 valence electrons, it does not have 8 valence electrons as the student suggested. It was grouped together with the noble gases because it exhibits similar properties with them.

5 0

3 years ago