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3 years ago

8

If the pressure of the reactants increase, What happens to the product.

1 answer:

EastWind [94]3 years ago

7 0

Increasing the pressure on a reaction involving reacting gases increases the rate of reaction. Changing the pressure on a reaction which involves only solids or liquids has no effect on the rate.

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Marcia is given an incomplete chemical equation that includes the number of nitrogen atoms present in the products of the reacti

Anna [14]

Answer: There would have to be three nitrogen atoms in the products. The law of conservation of matter states that the amount of substance before a reaction occurs should be the same as the amount of substance after the reaction.

Explanation: This is the EXACT sample answer from the test, just reword it if you want. ^

7 0

3 years ago

PLEASE PLEASE HELP!

valentinak56 [21]

Answer: The number of grams of $H_2$ in 1620 mL is 1.44 g

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = 1620 ml = 1.62 L (1L=1000ml)

n = number of moles = ?

R = gas constant = $0.0821Latm/Kmol$

T =temperature = $273K$

$n=\frac{PV}{RT}$

$n=\frac{1atm\times 16.2L}{0.0821Latm/K mol\times 273K}=0.72moles$

Mass of hydrogen = $moles\times {\text {Molar mass}}=0.72mol\times 2g/mol=1.44g$

The number of grams of $H_2$ in 1620 mL is 1.44 g

8 0

3 years ago

What is the correct order of sediment size from smaller particles to bigger particles?

Dimas [21]

It would be.. sand, slit, clay.

6 0

3 years ago

How many grams of aluminum sulfide would form if 2.25 liters of a 1.50 molar aluminum chloride solution reacts with 2.00 liters

Alex787 [66]

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8 0

3 years ago

A piece of glass has a temperature of 83˚C. Liquid that has a temperature of 43˚C is poured over the glass, completely covering

Lerok [7]

Answer: The specific heat of the liquid is $2520J/kg^0C$

Explanation:

$heat_{absorbed}=heat_{released}$

As we know that,

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

.................(1)

where,

q = heat absorbed or released

= mass of glass = x kg

= mass of liquid = x kg

= final temperature =

$T_1$ = temperature of glass = $83^oC$

$T_2$ = temperature of liquid = $43^oC$

$c_1$ = specific heat of glass = $840J/kg^0C$

$c_2$ = specific heat of liquid= ?

Now put all the given values in equation (1), we get

$-[(x\times 840\times (53-83)]=x\times c_2\times (53-43)$

$c_2=2520J/kg^0C$

Therefore, the specific heat of the liquid is $2520J/kg^0C$

5 0

3 years ago