Why is having a large mass not the only way to get a high momentum?

Physics

1 answer:

blondinia [14]2 years ago

5 0

Do large mass and small mass have the same momentum?

To Be Discovered... It Floats! Learn more physics! if a large mass and small mass have the same momentum, which has the greater kinetic energy? Let's have 2 objects, X1 and X2. They have the masses m1 and m2, with X1 being the big mass and X2 being the small mass, so X1 is the larger object. Their momentums are p1 and p2, respectively.

What causes momentum to double with mass? An unbalanced force acting upon an object always results in the momentum. Mass times velocity of any object stands as momentum. It generally doubles when the velocity gets increased. Additionally, if the two objects are moving with the same velocity, but having different mass, the momentum will be large for the object having large mass.

What is momentum and how is it defined?

Mass times velocity of any object stands as momentum. It generally doubles when the velocity gets increased. Additionally, if the two objects are moving with the same velocity, but having different mass, the momentum will be large for the object having large mass. Kgm/s is the unit to define momentum. What is a Force?

Why is momentum dependent on both mass and velocity?

This means that a massive body also possess greater quantity of motion. So from here , we simply notice that momentum is dependent on mass. Summing up the two cases , we get that momentum (the quantity of motion) is dependent on both mass and velocity. Other answers have shown why it can't be mass times velocity squared or any other .

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Two protons move with uniform circular motion in the presence of uniform magnetic fields. Proton one moves twice as fast as prot

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Answer:

r₂ = 4 r

Explanation:

For this exercise let's use Newton's second law with the magnetic force

F = q v x B

bold letters indicate vectors, the magnitude of this expression is

F = q v B sin θ

in this case we assume that the angle is 90º between the speed and the magnetic field.

If we use the rule of the right hand with the positive charge, the thumb in the direction of the speed, the fingers extended in the direction of the magnetic field, the palm points in the direction of the force, which is towards the center of the circle, therefore the force is radial and the acceleration is centripetal

a = v² / r

let's use Newton's second law

F = ma

q v B = m v² / r

r = $\frac{qB}{mv}$