Answer:
Explanation:
Given
Ship A velocity is 40 mph and is traveling 35 west of north
Therefore in 2 hours it will travel 
thus its position vector after two hours is

similarly B travels with 20 mph and in 2 hours
![=20\times 2=40 miles Its position vector[tex]r_B=40sin80\hat{i}+40cos80\hat{j}](https://tex.z-dn.net/?f=%3D20%5Ctimes%202%3D40%20miles%20%3C%2Fp%3E%3Cp%3EIts%20position%20vector%5Btex%5Dr_B%3D40sin80%5Chat%7Bi%7D%2B40cos80%5Chat%7Bj%7D)
Thus distance between A and B is



Velocity of A

Velocity of B

Velocity of A w.r.t B


Answer:
Explanation:
a ) speed of passenger = circumference / time
= 2π R / Time
= 2 x 3.14 x 50 / 60
= 5.23 m /s
b )
centrifugal force = m v² /R
= (882 /9.8 ) x 5.23² / 50
= 77.47 N
Apparent weight at the highest point
real weight - centrifugal force
= 882 - 77.47
= 804.53 N
Apparent weight at the lowest point
real weight + centrifugal force
= 882 +77.47
= 959.47 N
c ) if the passenger’s apparent weight at the highest point were zero
centrifugal force = weight
mv² /R = mg
v² = gR
= 9.8 X 50
v = 22.13 m /s
d )
apparent weight
mg - mv² / R
= 882 - (882 / 9.8 )x 22.13²/50
= 882 + 882
= 1764 N
=
Answer:
The rock will reach 9 m from the ground at eaxactly 5.06 s after it was initially thrown upwards.
Explanation:
We will use the equations of motion for this.
u = initial velocity of the rock = 22 m/s
g = acceleration due to gravity = -9.8 m/s²
y = vertical position of the rock at a time t = 9 m
y₀ = initial height of the rock = 25 m
t = time it takes for the rock to reach height of 9 m.
(y-y₀) = ut + 0.5gt²
(9 - 25) = 22t + 0.5(-9.8)t²
- 14 = 22t - 4.9t²
4.9t² - 22t - 14 = 0
solving this quadratic equation,
t = 5.055 s or - 0.565 s
Since time cannot be negative,
t = 5.055 s = 5.06 s
Hope this Helps!!!
Answer: Tissue.
Molecules make up cells, cells make up tissue, tissue makes up organs, organs make up organ systems.