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Tpy6a [65]
2 years ago
6

Can u pls help me i ​

Physics
1 answer:
kumpel [21]2 years ago
7 0

Answer:

I believe it's the Supreme Court issued a decision making segregation on buses illegal

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If a force of 10 N acts on an object and an additional force of 6 N acts on the object in
PIT_PIT [208]

Answer:

D

Explanation:

For this kind of problem, forces add. F = F1 + F2

F1 = 6 N

F2 = 10 N

F = 6N + 10N

F = 16N

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3 years ago
Light traveling though air strikes the surface of the four different materials shown. Which material reflects light but does not
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The spoons .................
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What is the rabbit's displacement from t = 0s to 3 s?<br> Answer with two significant digits.
Inessa05 [86]

Answer: i think the answer is 20.0s

Explanation:

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3 years ago
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A child is playing on a swing. As long as he does not swing too high the time it takes him to complete one full oscillation will
Aleks [24]

Answer:

We know that for a pendulum of length L, the period  (time for a complete swing) is defined as:

T = 2*pi*√(L/g)

where:

pi = 3.14

L = length of the pendulum

g = gravitational acceleration = 9.8 m/s^2

Now, we can think on the swing as a pendulum, where the child is the mass of the pendulum.

Then the period is independent of:

The mass of the child

The initial angle

Where the restriction of not swing to high is because this model works for small angles, and when the swing is to high the problem becomes more complex.

7 0
3 years ago
Um corpo de massa 50g recebe 300 calorias e sua temperatura sobe de -10°C até 20°C. Determine a capacidade térmica do corpo e o
kykrilka [37]

The specific heat capacity of the substance is 0.963 J/g^{\circ}C

Explanation:

When an object of mass m is supplied with a certain amount of energy Q, its temperature increases according to the equation:

Q=mC_s \Delta T

where

m is the mass of the object

C_s is its specific heat capacity

\Delta T is the increase in temperature of the object

In this problem, we have

Q=300 cal \cdot 4.814 = 1444.2 J

m = 50 g

\Delta T = 20C-(-10C)=30^{\circ}C

Therefore, we can solve for C_s to find its specific heat capacity:

C_s = \frac{Q}{m\Delta T}=\frac{1444.2}{(50)(30)}=0.963 J/gC

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

7 0
4 years ago
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