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Tpy6a [65]
2 years ago
6

Can u pls help me i ​

Physics
1 answer:
kumpel [21]2 years ago
7 0

Answer:

I believe it's the Supreme Court issued a decision making segregation on buses illegal

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A potter's wheel moves uniformly from rest to an angular speed of 0.16 rev/s in 31 s. (a) Find its angular acceleration in radia
dem82 [27]

Answer:

a) 0.0324 rad/s²

b) 2.01 rad/s , the final angular speed gets doubled

Explanation:

w₀ = initial angular speed = 0 rad/s

w = final angular speed = 0.16 rev/s = 0.16 (6.28) = 1.005 rad/s

t = time interval = 31 s

α = angular acceleration

final angular speed is given as

w = w₀ + α  t

1.005 = 0 + α (31)

α = 0.0324 rad/s²

b)

After the acceleration is doubled

α' = 2 α = 2 (0.0324) = 0.0648 rad/s²

w' = final angular speed

w'₀ = initial angular speed = 0 rad/s

final angular speed is given as

w = w₀ + α  t

w = 0 + (0.0648) (31)

w = 2.01 rad/s

yes the final angular speed gets doubled

8 0
4 years ago
A time-dependent but otherwise uniform magnetic field of magnitude B0(t) is confined in a cylindrical region of radius 6.5 cm. I
Papessa [141]

Answer:

The acceleration is   a = 3.45*10^{3} m/s^2

Explanation:

 From the question we are told that

         The radius is  d = 6.5 cm = \frac{6.5}{100} = 0.065 m

           The magnitude of the magnetic field is  B = 5.5 T

           The rate at which it decreases is  \frac{dB}{dt}  = 24.5G/s = 24.5*10^{-4} T/s

             The distance from the center of field is  r = 1.5 cm = \frac{1.5}{100} = 0.015m

  According to Faraday's law

          \epsilon = - \frac{d \o}{dt}

and   \epsilon = \int\limits  {E} \, dl

 Where  the magnetic flux \o = B* A

             E is the electric field  

             dl is a unit length

 So

         \int\limits  {E} \, dl = - \frac{d}{dt} (B*A)

         {E}  l = - \frac{d}{dt} (B*A)

Now l is the circumference of the circular loop formed by the magnetic field and it mathematically represented as  l = 2\pi r

A is the area  of the circular loop formed by the magnetic field and it mathematically represented as  A= \pi r^2

So

    {E}  (2 \pi r)= -  \pi r^2 \frac{dB}{dt}

    E = \frac{r}{2} [ - \frac{db}{dt} ]  

Substituting values  

    E = \frac{0.015}{2} (24*10^{-4})

         E = 3.6*10^{-5} V/m

The negative signify the negative which is counterclockwise

 

  The force acting on the proton is mathematically represented as

                       F_p = ma

        Also       F_p = q E

So

           ma = qE

 Where m is the mass of the the proton which has a value of  m = 1.67 *10^{-27} kg

 q = 1.602 *10^{-19} C

     So

            a =\frac{1.60 *10^{-19} *(3.6 *10^{-5}) }{1.67 *10^{-27}}

               a = 3.45*10^{3} m/s^2

                   

     

               

8 0
3 years ago
Pablo is asked to think about his favorite birthday party, and he pictures a cake with candles and frosting and he can even reme
Veseljchak [2.6K]
The correct answer is B. Analogical
4 0
4 years ago
If humans cannot see ultraviolet waves, how can ultravoilet light be used to gather evidence of a crime?
mafiozo [28]

Answer: The question is incomplete because the options are not given here are the options gotten from Another website.

A. Ultraviolet light detects the presence of radioactive substances.

B.Ultraviolet light shows cold areas as blue and warm areas as red.

C.Ultraviolet light causes substances to fluoresce and give off visible light.

D. Ultraviolet light transmits information to AM and FM radio receivers.

The correct option is C.

Ultraviolet light causes substances to fluoresce and give off visible light

Explanation:

This is because UV light radiates at a very short wavelengths compared to visible light which is impossible for humans to see it. Therefore , when UV light is absorbed by some particular materials, it reflect back towards the eye as visible radiation with a longer wavelength .This process is called UV-induced visible fluorescence.

4 0
3 years ago
charge, q1 =5.00μC, is at the origin, a second charge, q2= -3μC, is on the x-axis 0.800m from the origin. find the electric fiel
IRISSAK [1]

Answer:

Explanation:

Electric field due to charge at origin

= k Q / r²

k is a constant , Q is charge and r is distance

= 9 x 10⁹ x 5 x 10⁻⁶ / .5²

= 180 x 10³ N /C

In vector form

E₁ = 180 x 10³ j

Electric field due to q₂ charge

= 9 x 10⁹ x 3 x 10⁻⁶ /.5² + .8²

= 30.33 x 10³ N / C

It will have negative slope θ with x axis

Tan θ = .5 / √.5² + .8²

= .5 / .94

θ = 28°

E₂ = 30.33 x 10³ cos 28 i - 30.33 x 10³ sin28j

= 26.78 x 10³ i - 14.24 x 10³ j

Total electric field

E = E₁  + E₂

= 180 x 10³ j +26.78 x 10³ i - 14.24 x 10³ j

= 26.78 x 10³ i + 165.76 X 10³ j

magnitude

= √(26.78² + 165.76² ) x 10³ N /C

= 167.8 x 10³  N / C .

3 0
4 years ago
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