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Stella [2.4K]
2 years ago
11

How much time is required for an elevator to lift a 2000 kg load up 28 m from the ground level, if the motor can produce 13 kW o

f power?
Physics
1 answer:
morpeh [17]2 years ago
3 0

Answer:

W = P * t      work = work/time * time

t = W / P       time required

t = 2000 kg * 9.8 m/s2 * 28 m / P = 549,000 J / 13000 J/s

t = 42.2 sec

Note:  1 kW = 1000 J/sec

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A car is traveling at a speed of 54 km/h. Breaks are applied so as to produce a uniform acceleration of -0.5 m/s2. Find how far
Lena [83]

Explanation:

u=54 km/h

54*5/18=15 m/s

v=0m/s

t=?

acceleration=-0.5m/s^2

we know that a=v-u/t

so,

t=v-u/a

t=15-0/0.5

=15/0.5

=30

therefore, the time is 30 second

Hope this answer helps you..

8 0
3 years ago
If you had started with a larger mass, how would the half-life change?
iogann1982 [59]

Answer:

There is no change, unless your mass is somehow at the quantum level, at which the concept of half-life breaks down.

Half life is a property of the specific radioactive isotope...NOT of the initial sample's mass.

3 0
3 years ago
A net force acting on an object will always cause a change in the object's _________.
Nataly [62]
 cause a change in the object's velocity
3 0
3 years ago
A supertanker ( = 1.70 × 108 kg) is moving with a constant velocity. Its engines generate a forward thrust of 7.40 × 105 N. Dete
a_sh-v [17]

Answer:

(a) 0 (b) F=1.67\times 10^9\ N

Explanation:

Given that,

Mass of a supertanker, m=1.7\times 10^8\ kg

The engine of a generate a forward thrust of, F=7.4\times 10^5\ N

(a) As the supertanker is moving with a constant velocity. We need to find the magnitude of the resistive force exerted on the tanker by the water. It is given by :

F = ma, a is the acceleration

For constant velocity, a = 0

So, F = 0

(b) The magnitude of the upward buoyant force exerted on the tanker by the water is equal to the weight of the ship.

F = mg

F=1.7\times 10^8\times 9.8\\\\F=1.67\times 10^9\ N

Hence, this is the required solution.

4 0
3 years ago
A car starts from rest with an acceleration of 8 m/s/s for a time of 4 s. What was the car's final velocity?
Aleks [24]
32m/s
8m/s x 4s= 32m/s
6 0
3 years ago
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