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BARSIC [14]
2 years ago
8

A 2 kg ball of putty moving to the right at 3 m/s has a perfectly inelastic, head-on collision with a 1 kg ball of putty moving

at 2 m/s. What is the final magnitude and direction (left or right) of the velocity of the balls after the collision?
Physics
1 answer:
Aneli [31]2 years ago
5 0

Answer:

V=1.33m/s   to the right

Explanation:

The balls collide in a completely inelastic collision, in other words they have the same velocity after the collision, this velocity has a magnitude V.

We need to use the conservation of momentum Law, the total momentum is the same before and after the collision.

In the axis X:

m_{1}*v_{o1}-m_{2}*v_{o2}=(m_{1}+m_{2})V     (1)

V=(m_{1}*v_{o1}-m_{2}*v_{o2})/(m_{1}+m_{2})=(2*3-1*2)/(2+1)=1.33m/s

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N_{2}=20 turns

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