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SSSSS [86.1K]
2 years ago
6

If the frequency of the wave is 100 hz, what is the period of the wave?.

Physics
1 answer:
Cerrena [4.2K]2 years ago
3 0
Answer:
Time= 1/frequency
=1/100
=0.01
Explanation:

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Every football field has two 300kg field goal posts separated by 110m of football field (that includes the endzones). What is th
Mama L [17]

Answer:

4.96×10¯¹⁰ N

Explanation:

The following data were obtained from the question:

Mass 1 (M1) = 300 Kg

Mass 2 (M2) = 300 Kg

Separating distance (r) = 110 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Gravitational force (F) =?

The gravitational force between the two goal posts can be obtained as follow:

F = GM1M2 / r²

F = 6.67×10¯¹¹ × 300 × 300 / 110²

F = 6.003×10¯⁶ / 12100

F = 4.96×10¯¹⁰ N

Therefore the gravitational force between the two goal posts is 4.96×10¯¹⁰ N

3 0
2 years ago
4.
xxTIMURxx [149]
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3 0
2 years ago
Imagine a ringing bell set inside a sealed glass jar. Once all the air is removed and a vacuum is crated, the ringing sound is n
kenny6666 [7]

working...

Sound wave needs medium to travel

as energy which travels in this wave is because of transfer from one particle to another particle

If there is no medium then energy can not be transferred and sound wave will not travel

so in vacuum we can not listen sound

similarly here air is removed it means there is no medium inside the jar to travel the sound and hence we can not hear it

Option B is correct

Without air, the sound waves cannot travel to the ear.

5 0
3 years ago
Which career professionals are part of the Architecture and Construction career cluster? Check all that apply.
oksian1 [2.3K]

Answer:

A,B,D,E,F

Explanation:

I took the test for yall.

3 0
3 years ago
A stone is dropped from from rest at the top of a mine shaft. It takes 95 seconds for the stone to fall to the bottom of the min
Marianna [84]

Distance of fall from rest,
without air resistance              =  (1/2) (gravity) (time)²

                                             = (1/2) (9.8 m/s²) (95 sec)²

                                             =  (4.9 m/s²) (9,025 sec²)

                                             =        44,222.5 meters  .

The depth of the mine shaft is five times the height of Mt. Everest !


6 0
2 years ago
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