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monitta
3 years ago
10

If one star has a temperature of 5200 K and another star has a temperature of 7900 K, how much more energy per second will the h

otter star radiate from each square meter of its surface?
Physics
1 answer:
Natalija [7]3 years ago
5 0

Answer:

5.327

Explanation:

Stefan-Boltzmann law states that the total radiant heat power emitted from a surface is proportional to the fourth power of its absolute temperature.

                                     W = σT⁴

Where,

W is the total radiant heat power emitted from a surface

σ is  constant of proportionality, called the Stefan–Boltzmann constant = 5.67 × 10⁻⁸ Wm⁻²K⁻⁴

T is absolute temperature in kelvin

For the first star, T = 5200 K

                          ∴  W₁ = σ(5200)⁴

For the second star, T = 7900 K

                          ∴  W₂ = σ(7900)⁴

The amount of energy radiated by the hotter star W₂, with respect to the other star W₁  is,

                       W₂ / W₁  = σ(7900)⁴ / σ(5200)⁴

                        \frac{W_{2}}{W_{1}} = \frac{79^{4}}{52^{4}}

                        \frac{W_{2}}{W_{1}} = 5.327

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consider the motion in Y-direction

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- 0.89 = (25.6) t + (0.5) (- 9.8) t²

t = 5.3 sec


consider the motion along the horizontal direction :

v₀ = initial velocity = 29 Cos62 = 13.6 m/s

a = acceleration = 0 m/s²

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using the equation

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X = 72.1 m


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3 0
3 years ago
Earth can be modeled with five layers based on the strengths and physical properties of the materials in them. Put the layers in
andre [41]

Answer:

Crust, Upper mantle, mantle, outer core, inner core

Explanation:

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3 years ago
Which describes the relationship between photon energy and the color of light?
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3 0
3 years ago
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The potential energy stored in the compressed spring of a dart gun, with a spring constant of 32.50 N/m, is 0.640 J. Find by how
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Answer:

A

   x = 0.198456 \ m

B

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C

 v =  5.06 \  m/s

D

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Explanation:

Considering the first question

From the question we are told that

   The spring constant is  k  =  32.50 N/m

    The potential energy is  PE  =  0.640 \ J

Generally the potential  energy stored in spring  is mathematically represented as   PE  =  \frac{1}{2}  *  k  *  x^2

=>    0.640=  \frac{1}{2}  * 32.50  *  x^2  

=>    x = \sqrt{0.03938}  

=>    x = 0.198456 \ m  

Considering the second question

 From the question we are told that

   The mass of the dart is  m =  0.050 kg

Generally from the law of energy conservation

         PE =  mgh

=>       0.640   =  0.050 *  9.8  *  h

=>      h  =  1.3061 \  m

Considering the third  question

   The height at which the dart was fired horizontally is  H  =   3.90\  m

Generally  from the law of energy conservation

         PE = KE

Here  KE is kinetic energy of the dart which is mathematical represented as

     KE  =  \frac{1}{2}  *  mv^2

=>      0.640 =  \frac{1}{2}  * 0.050 *  v^2

=>       v^2 = 25.6

=>       v =  5.06 \  m/s

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Generally the total time of flight of the dart is mathematically represented as

       t  =  \frac{ 2 *  H }{g}

=>     t  =  \frac{ 2 * 3.90 }{9.8 }

=>     t  =  0.7959 \ s

Generally the  horizontal distance from the equilibrium position to the ground is  mathematically represented as

       d =  v  *   t

=>     d = 5.06  *   0.7959

=>     d = 4.0273 \  m

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3 years ago
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katrin [286]

Answer:

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3 years ago
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