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Ivanshal [37]
2 years ago
12

Which statement best describes the acceleration of the box? A) The box accelerates at 1. 0 m/s squared to the right because the

net force is 17N to the right B) The box accelerates at 1. 9 m/s squared to the right because the greater force is to the right C) The box accelerates at 3. 0 m/s squared because the combined forces cause the box to accelerate D) The box does not accelerate, because neither force is large enough to move the box.
Physics
1 answer:
Korolek [52]2 years ago
6 0

The box accelerates at 1. 0 m/s² to the right because the net force is 17N to the right . This statement clearly depicts the relation between force and acceleration. Hence option A is correct.

<h3>What is acceleration?</h3>

Acceleration is defined as the rate of change of the velocity of the body. Its unit is m/sec².It is a vector quantity. It requires both magnitudes as well as direction to define.

According to Newton's second law of motion, the net force acting on the body is equal to the product of mass and acceleration of the body.

The direction of acceleration is in the direction of net force acted.

Hence option A is correct.

To learn more about acceleration refer to the link;

brainly.com/question/969842

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A copper cable needs to carry a current of 160 A with a power loss of only 2.0 W/m. What is the required radius of the copper ca
lesantik [10]

Answer:

The radius of the cable is 0.0083 m or 8.3 mm.

Explanation:

The resistance of copper cable of 1 meter length will be given by

R_{cable} = \frac{\rho \times l}{a}    ....     (i)

where the resistivity of copper is \rho = 1.7 \times 10^{-8} \Omega.m , and l is the length of the wire which is considered to be 1m, and a is the cross sectional area of the wire in m^{2}.

From the formula of power we know that, P = I^2 R    ....    (ii)

Therefore 2 W/m  = (160)^2 \times R     ....     (iii)  

where  the resistance,R, actually means the resistance of the cable per meter.

Therefore R ( resistance of cable per meter)

= \frac{2}{160^2}  = 7.812 \times 10^{-5} ohms / meter.       ....    (iv)

Therefore from (i)

7.812 \times 10^{-5} = \frac{1.7 \times 10^{-8} \times 1}{a}  = \frac{1.7 \times 10^{-8} \times 1}{\pi r^{2} }       .....     (v)

where cross sectional area of the cable, a  = \pi r^2,

where r is the radius of the cable, and length of cable,l = 1m.

Therefore r  = \sqrt{\frac{ 1.7 \times 10^{-8}}{\pi \times 7.812 \times 10^{-5} } }  =  0.0083m = 8.3 mm

5 0
3 years ago
What is required to cause acceleration
Vesna [10]
Constant force. Basicly in no gravity you have to keep puching smth for it to accelerate and once you stop it just would remain at the same speed. On earth the fact that something is falling faster and faster means it keeps beeing constantly pulled by gravity so the same principle applies
6 0
3 years ago
Read 2 more answers
In cats, short hair is dominant and long hair is recessive. If a cat has the genotype of hh, what type of hair will it have?
raketka [301]

Answer:

long hair

Explanation:

long hair = hh

short hair= HH

and medium= Hh

8 0
3 years ago
The end point of a spring oscillates with a period of 2.0 s when a block with mass m is attached to it. When this mass is increa
Nostrana [21]

Answer: The end point of a spring oscillates with a period of 2.0 s when a block with mass m is attached to it. When this mass is increased by 2.0 kg, the period is found to be 3.0 s.  Then the mass m is 0.625kg.

Explanation: To find the answer, we need to know more about the simple harmonic motion.

<h3>What is simple harmonic motion?</h3>
  • A particle is said to execute SHM, if it moves to and fro about the mean position under the action of restoring force.
  • We have the equation of time period of a SHM as,

                                          T=2\pi \sqrt{\frac{m}{k} }

  • Where, m is the mass of the body and k is the spring constant.
<h3>How to solve the problem?</h3>
  • Given that,

               T_1=2s\\m_1=m\\m_2=m+2kg\\T_2=3s

  • We have to find the value of m,

              T_1=2\pi \sqrt{\frac{m}{k} } \\T_2=2\pi \sqrt{\frac{m+2}{k} } \\\frac{T_1}{T_2} =\sqrt{\frac{m}{m+2} }\\\frac{2}{3} =\sqrt{\frac{m}{m+2} }\\\\

               m=\frac{5}{8} =0.625kg

Thus, we can conclude that, the mass m will be 0.625kg.

Learn more about simple harmonic motion here:

brainly.com/question/28045110

#SPJ4

3 0
2 years ago
When jogging outside you accidently bump into a curb. Your feet stop but your body continues to move forward and you end up on t
oee [108]
Inertia I think because I've heard it around school and in science
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3 years ago
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