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2 years ago

Please help me find this answer

Physics

2 answers:

djyliett [7]2 years ago

5 0

Answer:

155/62 = 2.5

Mass/Volume = Density

Density= 2.5

Explanation:

Romashka [77]2 years ago

3 0

The equation is given. We know there is 155g and 62cm^3.

therefore the equation is 155g/ 62cm^3 giving you 2.5 as the density.

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Microwaves and infrared waves are similar because they both have

Alex787 [66]

The both have radiation waves. I hope this helps!

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3 years ago

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A rock is thrown upward from level ground in such a way that the maximumheight of its flight is equal to its horizontal rangeR.

Snowcat [4.5K]

A) The vertical component of velocity v is taking the rock to a height

Vertical component = $vsin\theta$
The time taken to reach maximum height = $\frac{vsin\theta}{g}$
So total time of rocks flight = $\frac{2vsin\theta}{g}$
Range of rock is due to the horizontal component of velocity = $vcos\theta$
Range = $\frac{2*v*sin\theta*v*cos\theta}{g}$ = $\frac{2*v^2*sin\theta*cos\theta}{g}$
Maximum height = $\frac{g*t^2}{2}$ = $\frac{v^2*sin^2\theta}{2*g}$
Since range = maximum height
We have $\frac{2*v^2sin\theta*cos\theta}{g} = \frac{v^2*sin^2\theta}{2*g}$
$tan\theta = 4$
$\theta = 75.96^0$
So when angle of projection is $\theta = 75.96^0$ range is equal to maximum height reached.
b) We have range = $\frac{2*v^2*sin\theta*cos\theta}{g}$ = $\frac{2*v^2*sin2\theta}{g}$
Maximum of range is reached when $\theta = 45^0$
Maximum range = $\frac{2*v^2}{g}$
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3 years ago

Jack and Jill exercise in a 25.0 m long swimming pool. Jack swims 9 lengths of the pool in 156.9 s ( 2 min and 36.9 s ) , wherea

Leya [2.2K]

Answer:

Jill average velocity is 0

Jack average velocity is 0.159337

Jill average speed = 1.593372

Jack average speed = 1.434034

Explanation:

given data

long swimming pool = 25.0 m

9 lengths of the pool = 156.9 s ( 2 min and 36.9 s )

10 lengths = same time interval

to find out

average velocity and average speed

solution

we know that average velocity that is express as

average velocity = $\frac{displacement}{time}$ .....................1

Jill come back where she start

so here velocity will be = 0

and

Jack ends up on the other end of pool

so average velocity = $\frac{25}{156.9}$

average velocity = 0.159337

now we get here average speed that is express as

average speed = $\frac{distance}{time}$ .............2

jack speed = 9 × $\frac{25}{156.9}$

jack speed = 1.434034

and

Jill speed = 10 × $\frac{25}{156.9}$

Jill speed = 1.593372

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4 years ago

A woman exerts a constant horizontal force on a large box. As a result, the box moves across a horizontal floor at a constant sp

d1i1m1o1n [39]

Answer:C

Explanation:

When a constant horizontal force is applied to the box, box started moving in the horizontal direction such that it moves with constant velocity $v_0$

Constant velocity implies that net force on the box is zero

i.e. there must be an opposing force which is equal to the applied force and friction force can serve that purpose.

So option c is the correct choice.

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4 years ago

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3 years ago