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Afina-wow [57]
3 years ago
8

A certain plucked string produces a fundamental frequency of 150 hz. Which frequency is not one of the harmonics produced by tha

t string?
Physics
1 answer:
Irina-Kira [14]3 years ago
6 0

Answer:

Some of the frequency that cannot be produced by the string includes 400Hz, 500Hz 650Hz etc...

Explanation:

Harmonics in strings are defined as the integral multiples of its fundamental frequency. This multiples are in arithmetic progression.

For example if Fo is the fundamental frequency of the string, the harmonics will be 2fo, 3fo, 4fo, 5fo... etc

If the string produces a fundamental frequency of 150Hz, some of the harmonics produced by the string will be 300Hz, 450Hz, 600Hz, 750Hz... etc

Some of the harmonics that cannot be produced include 400Hz, 500Hz 650Hz etc...

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Un tubo de acero de 40000 kilómetros forma un anillo que se ajusta bien a la circunferencia de la tierra. Imagine que las person
Darina [25.2K]

Answer:

82.76m

Explanation:

In order to find the distance of the steel ring to the ground, when its temperature has raised by 1°C, you first calculate the radius of the steel tube before its temperature increases.

You use the formula for the circumference of the steel ring:

C=2\pi r    (1)

C: circumference of the ring = 40000 km = 4*10^7m (you assume the circumference is the length of the steel tube)

you solve for r in the equation (1):

r=\frac{C}{2\pi}=\frac{4*10^7m}{2\pi}=6,366,197.724m

Next, you use the following formula to calculate the change in the length of the tube, when its temperature increases by 1°C:

L=Lo[1+\alpha \Delta T]         (2)

L: final length of the tube = ?

Lo: initial length of the tube = 4*10^7m

ΔT = change in the temperature of the steel tube = 1°C

α: thermal coefficient expansion of steel = 13*10^-6 /°C

You replace the values of the parameters in the equation (2):

L=(4*10^7m)(1+(13*10^{-6}/ \°C)(1\°C))=40,000,520m

With the new length of the tube, you can calculate the radius of a ring formed with the tube. You again solve the equation (1) for r:

r'=\frac{C}{2\pi}=\frac{40,000,520m}{2\pi}=6,366,280.484m

Finally, you compare both r and r' radius:

r' - r = 6,366,280.484m - 6,366,197.724m = 82.76m

Hence, the distance to the ring from the ground is 82.76m

4 0
3 years ago
Which quantity has both a magnitude and a
alexira [117]
(2) impulse is a vector quantity. Energy has no direction, nor does power. Work is a dot product of vector quantities, which makes it a scalar.
8 0
3 years ago
Read 2 more answers
A wave has a wavelength of 125 meters is moving at a speed of 20 m/s. What is it’s frequency?
Ann [662]

Answer: 0.16Hz

Explanation:

Given that:

wavelength (λ) = 125 meters

speed (V) = 20 m/s

frequency (F) = ?

Recall that frequency is the number of cycles the wave complete in one second. And its value depends on the wavelength and speed of the wave.

So, apply the formula V = F λ

Make F the subject formula

F = V / λ

F = 20 m/s / 125 meters

F = 0.16 Hz

Thus, the frequency of the wave is 0.16 Hertz.

4 0
3 years ago
Which object would have more potential energy, a bowling ball stored on a high shelf, or a base ball on the same shelf? Why? Whi
Anettt [7]

Answer:

A bowling ball stored on a high shelf has more potential energy

A base ball on the same shelf should rather fall on my head

Explanation:

Potential energy =mgh where m= mass, g= gravitational force and h is height

The bowling ball is bigger and heavier than the base ball

which means more mass . The remaining parameters are constant.

This means the bowling ball has more potential energy.

Since the base ball is lighter then it’s preferable to land on someone’s head due to the lesser force it will expert and lesser pain too.

7 0
3 years ago
If your acceleration speed is 15 m/s and you weigh 155 lbs, what is your gravitational force?​
sp2606 [1]

Answer:

Gravitational force, F = 1054.65 N

Explanation:

Given,

The accelerating speed, a = 15 m/s²

The mass of your body, m = 155 lbs

                                           = 70.31 Kg

The gravitational force acting in a body is given by the relation

                                F = m x g

Where g is the acceleration due to gravity of the in which the velocity of the body changes its speed at a constant rate.

                   ∴            a = g

Substituting the values in the above equation

                                  F = 70.31 x 15

                                     = 1054.65 N

Hence, the gravitational force acting on you, F = 1054.65 N

6 0
3 years ago
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