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2 years ago

Sandstone is a sedimentary rock. Which two processes cause sand particles to form sandstone?

Physics

2 answers:

slava [35]2 years ago

8 0

Answer:

number 2 is correct

Explanation:

cementation as icons are deposited by fluids to form a compound that hardens looses sedimentary rocks .

compaction is the density of sedimentary rocks on edge of them, are forced together though sediments mark me brainest add and follow me

yuradex [85]2 years ago

6 0

Answer:

Compaction and cementation

Explanation:

Cementation: As ions are deposited by fluids to form a compound that hardens loose sedimentary rocks.

Compaction: As the density of sedimentary rocks on edge of them are forced together through sediments.

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If the work done to stretch an ideal spring by 4.0 cm is 6.0 j, what is the spring constant (force constant) of this spring?

Alisiya [41]

Answer:

The spring constant is 3750 N/m

Explanation:

Use the following two relationships:

(Work) = (Force) x (Displacement)

(Force) = (Spring constant) x (Displacement)

(Spring constant) = (Force) / (Displacement) = (Work) / (Displacement)^2

(Spring constant) = 6.0 kg.(m^2/s^2) / 0.0016 m^2 = 3750 N/m

The spring constant is 3750 N/m

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3 years ago

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Brilliant_brown [7]

Answer:

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Explanation:

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2 years ago

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Misha Larkins [42]

6 . . . . . a crest
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9 . . . . . a trough

6 0

3 years ago

What's the name of the compound Kl?

Nat2105 [25]

Answer: Potassium iodide

Explanation: their you go

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2 years ago

Read 2 more answers

You and your friend throw balloons filled with water from the roof of a several story apartment house. You simply drop a balloon

Aleks [24]

Answer:

Height = 53.361 m

Explanation:

There are two balloons being thrown down, one with initial speed (u1) = 0 and the other with initial speed (u2) = 43.12

From the given information we make the following summary

$u_{1}$ = 0m/s

$t_{1}$ = t

$u_{2}$ = 43.12m/s

$t_{2}$ = (t-2.2)s

The distance by the first balloon is

$D = u_{1} t_{1} + \frac{1}{2} at_{1}^2$

where

a = 9.8m/s2

Inputting the values

$D = (0)t + \frac{1}{2} (9.8)t^2\\ D = 4.9t^2$

The distance traveled by the second balloon

$D = u_{2} t_{2} + \frac{1}{2} at_{2}^2$

Inputting the values

$D = (43.12)(t-2.2) + \frac{1}{2} (9.8)(t-2.2)^2$

simplifying

$D = 4.9t^2 + 21.56t -71.148$

Substituting D of the first balloon into the D of the second balloon and solving

$4.9t^2 = 4.9t^2 + 21.56t -71.148 \\ 21.56t = 71.148\\ t = 3.3s$

Now we know the value of t. We input this into the equation of the first balloon the to get height of the apartment

$D = 4.9(3.3)^2\\ D = 53.361 m$

7 0

2 years ago