The biggest thing you're doing wrong is ignoring the units
when you're working with the quantities.
Now let's look at the rest of the problem:
The formula you used is correct:
Net flux through the surface = (net charge inside) / ε₀
and ε₀ = 8.85 x 10⁻¹² farad/meter.
What's the net charge inside the surface in this problem ?
It's (5.85 x 10⁷ electrons) x (the charge on each electron)
= (5.85 x 10⁷ electrons) x (-1.6 x 10⁻¹⁹ coulomb/electron)
= -9.36 x 10⁻¹² coulomb .
Finally, (net charge inside) / ε₀
= (-9.36 x 10⁻¹² coulomb) / (8.85 x 10⁻¹² farad/meter)
= -1.058 newton-m²/coulomb .
The sign and the significant figures in your answer are correct, so
we can see that you know what you're doing. The only thing left is
the order of magnitude. You most likely took one of the negative
exponents and made it positive. You got an answer that's 10²² too
small. Big deal. You could claim "that's close", and see whether you
can convince a teacher.
Answer:
To prevent from getting injured.
Answer:
Explanation:
We shall represent all the forces in vector form .
Force of 95 pounds
F₁ = 95cos100 i + 95sin100j
= -16.5 i +93.55 j
force of 75 pounds
F₂ = 75cos200 + 75sin200j
= -70.47 i - 25.65 j
force of 146 pounds
F₃ = 146cos300 i + 146sin300j
= 73i -126.44 j
Resultant force
R = F₁+ F₂ + F₃
= -16.5 i +93.55 j -70.47 i - 25.65 j +73i -126.44 j
= -13.97 i - 58.54 j
Magnitude of R = √ ( 13.97² + 58.54² )
= 60.18
If Ф be angle of resultant with axis
tanФ = - 58.54 / -13.97
Ф = 76.57 + 180 = 256.57 , because both x and y components are negative. So the resultant will be in third quadrant.
Answer:
1.03m/s
Explanation:
According to the question
Fdrag = bv²
now Fdrag = weight of the box
that is Fdrag = mg
where m = mass of the box, 0.6 Kg
and g = acceleration due to gravity
thus,
Fdrag = bv² becomes
mg = bv²
making v the subject of formula
v = 1.03m/s
Answer:
car1: a=3.1m/s^2 , car2: a=6.1m/s^2
(a) 1/2*3.1*t^2= 1/2*6.1*(t-0.9)^2
1.55t^2= 3.05(t^2-1.8t+0.81)= 3.05t^2-5.49t+2.4705
1.5t^2-5.49t+2.4705= 0
t= 3.13457 = 3.14[s] after.
(b) d= 1/2*3.1*3.13457^2= 15.23[m] approx.
(c) car1: v=at = 3.1*3.13457= 9.717m/s
car2: v=at = 6.1*(3.13457-0.9)= 13.631m/s
13.631-9.717= 3.914 = 3.91[m/s] faster than car1.
