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hodyreva [135]
3 years ago
10

Difference between osmosis and diffusion

Chemistry
1 answer:
zysi [14]3 years ago
4 0
The answer is:  [A]:  "<span>Osmosis occurs through a semipermeable membrane" .
____________________________________________________________</span>
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Name three uses of satellite that effect every day?
fomenos
GPS- Global Positioning System, this is be found in cars
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Phone calls and text messages- the signals go from your phone to the satellite and back down to whoever you're texting.

Hope this helps :)
8 0
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How did the development of the earliest idea about atoms differ from the later work of scientists?
NISA [10]
The early ideas of the atom states that the indivisible object is hollow or is a solid object with nothing inside. The later discoveries or works of the scientists states that inside the atoms are the subatomic particles which are the electrons, protons, and neutrons. 
6 0
3 years ago
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A scientist is working in a lab and accidentally combines two liquids that quickly form a solution. Which process could be used
lions [1.4K]

Answer:

Heating the liquids and letting one boil away first :)

Explanation:

7 0
2 years ago
How might you add warm water to the beaker of cold water?
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You get a tub of warm water and tip the warm water into the cold water
7 0
3 years ago
Determine which of the following pairs of reactants will result in a spontaneous reaction at 25°C. None of the above pairs will
Alla [95]

Answer:

Only Fe^{3+}+Mg gives spontaneous reaction.

Explanation:

A redox reaction will be spontaneous if standard reduction potential (E^{0}) of the reaction is positive. Because it leads to negative standard gibbs free energy change (\Delta G^{0}), which is a thermodynamic condition for spontaneity of a reaction.

E^{0}=E^{0}(reduction)-E^{0}(oxidation)

Where E^{0}(reduction) and E^{0}(oxidation) represents standard reduction potential of reduction half cell and standard reduction potential of oxidation half cell.

(1) Oxidation:         Mg-2e^{-}\rightarrow Mg^{2+} ;  E_{Mg^{2+}\mid Mg}^{0}=-2.38V

Reduction:         Fe^{3+}+3e^{-}\rightarrow Fe ; E_{Fe^{3+}\mid Fe}^{0}=-0.04V

So, E^{0}=E_{Fe^{3+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}=(-0.04+2.38)V=2.34V

Hence this pair will give spontaneous reaction.

(2) Similarly as above, E^{0}=E_{Pb^{2+}\mid Pb}^{0}-E_{Au^{+}\mid Au}^{0}=(-0.13-1.69)V=-1.82 V

Hence this pair will give non-spontaneous reaction.

(3) Similarly as above, E^{0}=E_{Ag^{+}\mid Ag}^{0}-E_{Br_{2}\mid Br^{-}}^{0}=(0.80-1.07)V=-0.27 V

Hence this pair will give non-spontaneous reaction.

(4)  Similarly as above, E^{0}=E_{Li^{+}\mid Li}^{0}-E_{Cr^{3+}\mid Cr}^{0}=(-3.04+0.74)V=-2.30 V

Hence this pair will give non-spontaneous reaction.

6 0
3 years ago
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