<u>Answer:</u> The mass of tetraphosphorus decaoxide formed is 64.81g
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
....(1)
- <u>For potassium chlorate:</u>
Given mass of potassium chlorate = 93.3 g
Molar mass of potassium chlorate = 122.55 g/mol
Putting values in above equation, we get:
![\text{Moles of potassium chlorate}=\frac{93.3g}{122.55g/mol}=0.761mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20potassium%20chlorate%7D%3D%5Cfrac%7B93.3g%7D%7B122.55g%2Fmol%7D%3D0.761mol)
For the given chemical reaction:
![10KClO_3+12P\rightarrow 3P_4O_{10}+10KCl](https://tex.z-dn.net/?f=10KClO_3%2B12P%5Crightarrow%203P_4O_%7B10%7D%2B10KCl)
Red phosphorus is given in excess . So, it is considered as an excess reagent and potassium chlorate is considered as a limiting reagent.
By Stoichiometry of the reaction:
10 moles of potassium chlorate reacts with 3 moles of tetraphosphorus decaoxide
So, 0.761 moles of potassium chlorate will react with =
of tetraphosphorus decaoxide
Calculating the mass of tetraphosphorus decaoxide by using equation 1, we get:
Molar mass of tetraphosphorus decaoxide = 283.886 g/mol
Moles of tetraphosphorus decaoxide = 0.2283 moles
Putting values in equation 1, we get:
![0.2283mol=\frac{\text{Mass of tetraphosphorus decaoxide}}{283.886g/mol}\\\\\text{Mass of tetraphosphorus decaoxide}=64.81g](https://tex.z-dn.net/?f=0.2283mol%3D%5Cfrac%7B%5Ctext%7BMass%20of%20tetraphosphorus%20decaoxide%7D%7D%7B283.886g%2Fmol%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20tetraphosphorus%20decaoxide%7D%3D64.81g)
Hence, the mass of tetraphosphorus decaoxide formed is 64.81g