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Alex
2 years ago
8

An a.c. supply is connected to a wire stretched between the poles of a magnet. Which way does the wire move?​

Physics
1 answer:
snow_lady [41]2 years ago
7 0
The wire vibrates back and forth between the poles of the magnet.
The frequency of the vibration is the frequency of the AC supply.

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What is a net force on an object that has a mass of 20.0 kg, an applied force of 100 n moving on a surface with a friction coeff
sergiy2304 [10]

The net force on the object as described is; 58.84N

Two forces acting on the object are;

  • The <em>applied force and the frictional force.</em>

In essence; the frictional force can be evaluated as;

  • Frictional force; = coefficient × Weight of object.

  • Frictional force = 0.21 × 20 × 9.8.

  • Frictional force = 41.16N

  • The Net force = Applied force - frictional force

  • Net force = 100 - 41.16N

Net Force = 58.84 N.

Read more:

brainly.com/question/94428

5 0
3 years ago
Some ideal gas is constrained in the V"part of anadiabatic container of volume V" V$. The rest of the container is vacuum. When
solmaris [256]

Answer:

Using the log combination rules to reduce the famous Sakur-Tetrode equation, The change in entropy is given as:

∆S = NK*ln(V"V$/V").

Where V"V$ is final Volume (Vf) after constraint's removal,

V" is Initial Volume (Vi) before constraint's removal.

Temperature (T) is constant, Internal Energy, U is constant, N and K have their usual notations

Explanation:

Given in the question, the container is an adiabatic container.

For an adiabatic contain, it does not permit heat to the environment due to its stiff walls. This implies that the Internal Energy, U is kept constant(Q = U). The temperature is also constant (Isothermal). Thus, the famous Sakur-Tetrode equation will reduce to ∆S = NK* In(Vf/Vi).

Vf is the volume after the constraint is removed(Vf = V"V$). Vi is the volume occupied before the constraint is removed (Vi = V")

5 0
4 years ago
A crazy dog runs at a constant speed of 19.85 mi/hr for 6.09 min. How far does the dog travel during this time period?
Phantasy [73]

Answer:

Distance, d = 3242.19 meters

Explanation:

It is given that,

Speed of the dog, v = 19.85 mi/hr

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v = 19.85 mi/hr = 8.873 m/s

Time taken by the dog, t = 6.09 min = 365.4 sec

Let the distance covered by the dog during this time period is d. It can be calculated by the speed of the dog multiplied by the time taken as :

d=v\times t

d=8.873\times 365.4

d = 3242.19 meters

So, the the dog travel during this time period is 3242.19 meters. Hence, this is the required solution.

8 0
3 years ago
Procedure on making electricity using solar
OLga [1]
<span>Solar-powered photovoltaic (PV) panels convert the sun's rays into electricity by exciting electrons in silicon cells using the photons of light from the sun. This electricity can then be used to supply renewable energy to your home or business.</span>
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Between a piece of paper and a rock, which will fall the fastest and why?
AysviL [449]

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