Answer:
pH=4.05
Explanation:
C7H6O2 -> C7H6O- + H+
ka= [C7H6O-] [H+]/[C7H6O2]
During equilibrium
[C7H6O-]= [H+]= x^2
[C7H6O2]=0.12-x
Replace
ka= x^2/0.12-x
6.5 x10^-5= x^2/0.12-x
7.8x10^-6 - 6.5 x10^-5x=x^2
x^2+ 6.5 x10^-5x - 7.8x10^-6
Solution of quadratic equation
x=8.8 x10^-5
pH= -log [H+]= -log 8.8 x10^-5=4.05
C) convection cells (currents)
Explanation:
The movement of warmer cooler mantle rocks creating a circulation within the mantle is called a convection cell. These are the forces that drives the plate over asthenosphere.
- Convection is form of heat transfer predominant in liquids and gases.
- The mantle is molten and heated from heat within the core and the decay of radioactive bodies.
- Hot bodies are light and tend to be more buoyant. This causes warm mantle to rise to the surface.
- The cold part are denser and heavier, they sink in the mix.
- This creates pockets of circulation pattern within the mantle called convection cells.
Learn more:
Lithosphere brainly.com/question/9582362
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Answer:
- <u><em>The volume of CO₂(g) produced at STP when 0.05 moles of C₂H₄(g) was burnt in O₂(g) is 2.24dm</em></u><em><u>³</u></em>
Explanation:
The question is incomplete.
This is the complete question:
<em>Consider the reaction by the following equation:</em>
<em />
<em> C₂H₄(g) + 3O₂(g) → 2CO₂(g) + 2H₂O(g)</em>
<em />
<em>The volume of CO₂(g) produced at s.t.p when 0.05 moles of C₂H₄(g) was burnt in O₂(g) is ________</em>
<em />
<em>[Molar Volume of gas = 22.4dm³]</em>
<em />
<em> A. 1.12dm³</em>
<em> B. 2.24dm³</em>
<em> C. 3.72dm³</em>
<em> D. 4.48dm³</em>
<h2>Solution</h2>
<u />
<u>1. Write the mole ratio between CO₂(g) and C₂H₄(g)</u>
- 1 mol C₂H₄(g) : 2 mol CO₂(g)
<u>2. Multiply the 0.05 moles of C₂H₄(g) by the mole ratio</u>
- 0.05 mol C₂H₄ × 2 mol CO₂ / 1 mol C₂H₄(g) = 0.10 mol CO₂
<u>3. Convert moles of CO₂ to volume at STP using the molar volume at STP</u>
- 0.10 mol CO₂ × 22.4 dm³ / mol = 2.24 dm³
Answer:
= 0.551J/(g°C)
Explanation:
Specific heat is the amount of heat to required to raise the temperature of 1 gram substance to 1° C
The formula
C = q / m × ΔT ______ (1)
where ,
C = specific heat
q = heat
m = mass
ΔT = change in temperature
mass of the stainless steel is m = 1.55g
heat of the stainless steel is q = 141 J
the change in temperature is ΔT = 178°C
substitute all the value in the equation (1)
Copper is important in electrical works because copper has low resistivity, and therefore is an excellent conductor. Copper is also less oxidative than other metals.