2 years ago

Determine the empirical formula for a compound containing 85.6 g of carbon and 14.4 g of hydrogen. Please show work

Chemistry

1 answer:

photoshop1234 [79]2 years ago

4 0

Answer: $C_{1}H_{2}$

Explanation:

take gram & convert to mol (using the mm of the element) ,

85.6g C $\frac{1 mol }{12.01g}$ = 7.12 14.4g H $\frac{1 mol}{1.01g}$ =14.2 then take the smallest number & divide 7.12/7.12 =1 14.2/7.12= 2. since the numbers are in whole numbers the answer is $C_{1}H_{2}$ .

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