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Bumek [7]
3 years ago
5

Which is an example of colloid

Physics
1 answer:
bulgar [2K]3 years ago
7 0
Colloid mixtures can be solids, liquids, or gases. EX- Would include, butter, milk, and frog. There are actually 8 types of colloid mixtures, they are usally described by orginal state.
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A man ties one end of a strong rope 8.17 m long to the bumper of his truck, 0.524 m from the ground, and the other end to a vert
Kamila [148]

Answer:

2442.5 Nm

Explanation:

Tension, T = 8.57 x 10^2 N

length of rope, l = 8.17 m

y = 0.524 m

h = 2.99 m

According to diagram

Sin θ = (2.99 - 0.524) / 8.17

Sin θ = 0.3018

θ = 17.6°

So, torque about the base of the tree is

Torque = T x Cos θ x 2.99

Torque = 8.57 x 100 x Cos 17.6° x 2.99

Torque = 2442.5 Nm

thus, the torque is 2442.5 Nm.

8 0
4 years ago
Which of the the input Shelly does on a rake is 80J the output work the rate does on the leaves that 70 J what is the efficiency
Mumz [18]

Answer: The efficiency Shelly does is 87.5%.

(70J/80J) x 100% = 87.5%

Answer 2: Gravitational potential energy would be considered an object 10 meters above the ground.

6 0
3 years ago
What is the power of a refrigerator with voltage 110 V and<br> current 0.8 A?
tia_tia [17]

Answer: 88

Explanation:

8 0
3 years ago
A mountain climber increases their height from 200 meters to 400 meters. What affect will this have on their potential energy?
Yanka [14]

Answer:

At 400 m the potential energy of the mountain climber doubled the initial value.

Explanation:

Given;

initial height of the mountain climber = 200 m

final height of the mountain climber, = 400 m

The potential energy of the mountain climber is calculated as;

Potential energy, P.E = mgh

At 200 m, P.E₁ = mg x 200 = 200mg

At 400 m, P.E₂ = mg x 400 = 400mg

Then, at 400 m, P.E₂ = 2 x 200mg = 2 x P.E₁

Therefore, at 400 m the potential energy of the mountain climber doubled the initial value.

4 0
3 years ago
Projectiles Launched Horizontally Quiz
NikAS [45]

Answer:

3.0 seconds

Explanation:

The time of flight of a projectile (the time it takes to reach the ground) does not depend on the horizontal motion, but only on its vertical motion.

In fact, the time of flight is determined by the suvat equation:

s=ut+\frac{1}{2}gt^2

where

s is the vertical displacement

u is the initial vertical velocity (0, in case of these two projectiles)

g = 9.8 m/s^2 is the acceleration of gravity (assuming downward as positive direction)

t is the time of flight

Re-arranging the equation, we get

t=\sqrt{\frac{2s}{g}}

We see that this time depends only on s (the heigth of the cliff) and g: therefore, since the two projectiles are launched from the same height, they take the same time to reach the ground, 3.0 seconds.

7 0
3 years ago
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