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Gelneren [198K]
4 years ago
6

Is magnesium a metal or a nonmetal? How many valence electrons does a magnesium atom have?

Chemistry
2 answers:
MatroZZZ [7]4 years ago
6 0
Magnesium is classified as a metal. Magnesium has two valence electrons
Romashka-Z-Leto [24]4 years ago
3 0

<u>Answer:</u> The given element is a metal and the number of valence electrons are 2

<u>Explanation:</u>

There are 2 types of elements in the periodic table:

  • Metals are the elements which have a tendency to loose electrons and thus they form cations. <u>For Example:</u> Sodium will loose 1 electron to form Na^+ ion.
  • Non-metals are the elements which have a tendency to gain electrons and thus they form anions. <u>For Example:</u> Chlorine will gain 1 electron to form Cl^- ion.

Valence electrons are defined as the electrons which are present in the outermost shell of an atom. Outermost shell has the highest value of 'n' that is principal quantum number.

<u>We are given:</u>

Magnesium is the 12th element of the periodic table having electronic configuration of 1s^22s^22p^63s^2

This element will loose 2 electrons to form Mg^{2+} ion

Number of valence electron in magnesium element = 2

Hence, the given element is a metal and the number of valence electrons are 2

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having that coloration is selected for since many predators will recognize it and stay away. Therefore the common coloration is
garri49 [273]

Answer: Natural selection.

Explanation:

The natural selection is the process by which the organism that best suits the characters will survive and the organism which cannot adapt the changes will die.

The predators feed on their prey and the organism which hides easily in the environment due to its color is safe and the animals that cannot camouflage will die.

This is natural selection that more favored character is carried out over generations and other that cannot survive die.

5 0
4 years ago
Please help me like now please
777dan777 [17]

Answer:

1-1) NaHCO3 + CH3COOH --> NaCH3COO + H2O + CO2

1-2) 0.5 mole of CO2

2-1) 2C4H10 + 13O2 --> 8CO2 + 10H2O

2-2) 4 mol CO2

Explanation:

<u>Question 1</u>

NaHCO3 + CH3COOH --> NaCH3COO + H2O + CO2

<em>To balance the equation, count the number of atoms on both sides of the equation</em>

(1 Na, 1+3+1H, 1+1+1C, 3+2Oxygen) --> (1 Na, 1+1+1C, 3+2H, 2+1+2Oxygen)

<em>Combining the pluses will give you the following</em>

(1 Na, 5H, 3C, 5Oxygen) --> (1 Na, 3C, 5H, 5Oxygen)

<em>Both sides are the same, therefore the chemical equation is balanced (originally). </em>

From the equation, we can see that <u>1 mole of NaHCO3</u> produces <u>1 mole of CO2</u>.

So that means <u>0.5 mole of NaHCO3</u> would produce <u>0.5 mole of CO2</u>.

<u>Question 2</u>

C4H10 + O2 --> CO2 + H2O

<em>Again, count the number of atoms on both sides of the equation</em>

(4C, 10H, 2O) --> (1C, 2H, 3O)     <em>This time left does not equal right side</em>

<em>You now need to find </em><u><em>factors </em></u><em>that can make both sides equal. </em>

C4H10 + O2 --> <u>4</u>CO2 + H2O    <em>Now the C is balanced, let's recount </em>

<em>(4C, 10H, 2Oxygen) --> (4C, 8+1Oxygen, 2H)      H&O is still not balanced</em>

C4H10 + O2 --> 4CO2 + <u>5</u>H2O    <em>Now the H is balanced, let's recount</em>

<em>(4C, 10H, 2Oxygen) --> (4C, 8+5Oxygen, 10H)      O is still not balanced</em>

C4H10 + (<u>13/2</u>)O2 --> 4CO2 + 5H2O    <em>Now the O is balanced</em>

<em>(4C, 10H, 13Oxygen) --> (4C, 13Oxygen, 10H)</em>

<em>But because 13/2 is a fraction, we want to eliminate that by multiplying every reactant and product by 2 (the denominator).</em>

<u>2</u>C4H10 + <u>13</u>O2 --> <u>8</u>CO2 + <u>10</u>H2O    Now it's completely balanced!

<em>(8C, 20H, 28Oxygen) --> (8C, 28Oxygen, 20H)     Yayy! It's balanced.</em>

Now, 2 mol C4H10 produces 8 mol CO2.

So 1 mol C4H10 produces 4 mol CO2.

6 0
3 years ago
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Mashcka [7]

HEY DEAR..

The particles of light known as photon.

HOPE ITS HELPFULL

6 0
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kompoz [17]

Answer:

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Explanation:

The three-point test refers to a ground test utilizing an auxiliary current electrode and an auxiliary potential electrode.

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