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victus00 [196]
2 years ago
13

Energy from food

Physics
2 answers:
I am Lyosha [343]2 years ago
8 0

Answer:

all of the above I think??

Simora [160]2 years ago
5 0
The answers are 2) can be used to keep your heart beating and 3) keep your heart beating.
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What is the displacement of the particle in the time interval 7 seconds to 8 seconds? A. 0 meters B. 1.5 meters C. 3 meters D. 7
Dmitrij [34]

Answer: B. 1.5 meters

Explanation:

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Find the force between 2C and -1C separated by a distance 1m. Indicate if it is an attractive force (negative) or a repulsive fo
telo118 [61]

Answer:

Explanation:

Its definitely an Attractive force since the two charges are Unlike.

From Coulombs Law

F=kq1q2/R²

Given

K=9x10^9

R=1m

q1=2C

q2=-1C

F=(9x10^9 x 2 x -1)/1²

F= - 1.8x10^10N. (Attractive).

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3 years ago
Use Percentages Given that the molecular mass of magnesium
ira [324]

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27%

Explanation:

15.999 divided by 58.32 = .27433128

Move the decimal place over 2 places.

27%

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3 years ago
What are the differences between concave lens and concave mirrors?
Pavel [41]

Explanation:

A concave mirror can form real, inverted images of various sizes and virtual, erect and enlarged images whereas a concave lens forms only virtual, errect and diminished images.

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3 years ago
An inductor is connected to the terminals of a battery that has an emf of 16.0 V and negligible internal resistance. The current
balu736 [363]

Answer:

(a) The resistance R of the inductor is 2480.62 Ω

(b) The inductance L of the inductor is 1.67 H

Explanation:

Given;

emf of the battery, V = 16.0 V

current at 0.940 ms = 4.86 mA

after a long time, the current becomes 6.45 mA = maximum current

Part (a) The resistance R of the inductor

R = \frac{V}{I_{max}} = \frac{16}{6.45*10^{-3}} = 2480.62 \ ohms

Part (b)  the inductance L of the inductor

\frac{Rt}{L} = -ln(1-\frac{I}I_{max}})\\\\L = \frac{Rt}{-ln(1-\frac{I}I_{max})}}

where;

L is the inductance

R is the resistance of the inductor

t is time

L = \frac{Rt}{-ln(1-\frac{I}I_{max})}} = \frac{2480.62*0.94*10^{-3}}{-ln(1-\frac{4.86}{6.45})} \\\\L =\frac{2.3318}{1.4004} = 1.67 \ H

Therefore, the inductance is 1.67 H

5 0
3 years ago
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