Work, W = 277.269kJ
Internal energy, Q = 277.269kJ
<u>Explanation:</u>
Given-
Pressure, P1 = 2 bar
Temperature, T1 = 300K
Volume, V1 = 2m³
P2 = 1 bar
PV = constant
Let,
mass in kg be m
Work in kJ be W
Heat transfer in kJ be Q
R' = 8.314 kJ/kmolK
Mass of air, Mair = 28.97 kg/kmol
R = 0.289 kJ/kgK
We know,
PV = mRT
m = 5.65kg
To calculate V₂:
PV = constant = P₁V₁ = P₂V₂
P₁V₁ = P₂V₂
V₂ = 4m³
To calculate the work:
P₁V₁ = C
P₁ = C/ V₁
where limit is V₁ to V₂
To calculate heat transfer:
Q - W = Δu
Q - W = m (u₂ - u₁)
Q = W + m (u₂ - u₁)
Q = W + m X cv X (T₂ - T₁)
Since, T₁ ≈ T₂
There is no change of internal energy.
W = Q
Q = 277.269kJ
Answer:
I think the answer is B. Black
Answer:
resistance = 2.52 ohms
Explanation:
from the formula
V =IR
Voltage = (current)(resistance)
Resistance =
R=
R= 2.52 ohms
The examples of engineering controls is Biohazard waste containers and Spill clean up kits.
What is engineering controls?
An engineering controls is a workplace process that protect workers by removing hazardous conditions or by placing a barrier between the worker and the hazard.
An example of engineering controls is installation of exhaust ventilation to remove airborne emissions to shield the worker.
Hence, the examples of engineering controls is Biohazard waste containers and Spill clean up kits.
Therefore, the Option C and D is correct.
Answer:yes
Explanation:he divided by the numnebr of hockey pucks
