Answer:
The peak-to-peak ripple voltage = 2V
Explanation:
120V and 60 Hz is the input of an unfiltered full-wave rectifier
Peak value of output voltage = 15V
load connected = 1.0kV
dc output voltage = 14V
dc value of the output voltage of capacitor-input filter
where
V(dc value of output voltage) represent V₀
V(peak value of output voltage) represent V₁
V₀ = 1 - (
)V₁
make C the subject of formula
V₀/V₁ = 1 - (1 / 2fRC)
1 / 2fRC = 1 - (v₀/V₁)
C = 2fR ((1 - (v₀/V₁))⁻¹
Substitute for,
f = 240Hz , R = 1.0Ω, V₀ = 14V , V₁ = 15V
C = 2 * 240 * 1 (( 1 - (14/15))⁻¹
C = 62.2μf
The peak-to-peak ripple voltage
= (1 / fRC)V₁
= 1 / ( (120 * 1 * 62.2) )15V
= 2V
The peak-to-peak ripple voltage = 2V
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A N S W E R : –</h2>
Nothing happens to the brightness of the light bulbs in the parallel circuit if the power supply is capable of supplying the additional current.
Answer:
y = 2.196 m
Explanation:
Mass, m = 76 kg
distance from axis of rotation, x = 0.38 m
Second Force, F = 129 N
moment arm of the second force, y = ?
Now, equating moments for the equilibrium
So,
m g × x = F x y
76 x 0.38 x 9.81 = 129 x y
y = 2.196 m
Hence, the length of the moment arm is equal to 2.196 m.
Answer:
8.83m
Explanation:
Given parameters:
Acceleration = 7.8m/s²
Initial velocity = 0m/s
distance covered = 5m
Unknown:
Final velocity = ?
Solution:
The equation to solve this problem with is given as;
V² = U² + 2aS
V is the final velocity
U is the initial velocity
a is the acceleration
S is the distance
Input the parameters and solve;
V² = 0² + 2 x 7.8 x 5 = 78
V = √78 = 8.83m