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Artemon [7]
3 years ago
10

A book weighing 2.0 Newtons is lifted 3.0 meters in 4.0 seconds. How much work was done? SHOW WORK

Physics
1 answer:
qaws [65]3 years ago
7 0

6 Ns is the work done on the book to lift it by 3 m.

Answer:

Explanation:

Work done is the measure of amount of force required to move an object from its initial position to any desired position. So mathematically it can be calculated as the product of force acting on that object to the displacement of that object. Thus, work done on any object or by any object is directly proportional to the force acting on that object and the displacement of that object.

Work done = Force × displacement

As here the force is said to be 2 N and the displacement of the book is said to be 3 m, the work done on the book is

Work done = 2×3 = 6 N.s.

The time has no role to do on the work done calculation to be performed on the object.

Thus, 6 Ns is the work done on the book to lift it by 3 m.

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A certain unfiltered full-wave rectifier with 120 V, 60 Hz input produces an output with a peak of 15 V. When a capacitor-input
KATRIN_1 [288]

Answer:

The peak-to-peak ripple voltage = 2V

Explanation:

120V and 60 Hz is the input of an unfiltered full-wave rectifier

Peak value of  output voltage = 15V

load connected = 1.0kV

dc output voltage = 14V

dc value of the output voltage of capacitor-input filter

where

V(dc value of output voltage) represent V₀

V(peak value of output voltage) represent V₁

V₀ = 1 - ( \frac{1}{2fRC})V₁

make C the subject of formula

V₀/V₁ = 1 - (1 / 2fRC)

1 / 2fRC = 1 - (v₀/V₁)

C = 2fR ((1 - (v₀/V₁))⁻¹

Substitute  for,

f = 240Hz , R = 1.0Ω, V₀ = 14V , V₁ = 15V

C = 2 * 240 * 1 (( 1 - (14/15))⁻¹

C = 62.2μf

The peak-to-peak ripple voltage

= (1 / fRC)V₁

= 1 /  ( (120 * 1 * 62.2) )15V

= 2V

The peak-to-peak ripple voltage = 2V

3 0
3 years ago
A force of 20 N acts upon a 5 kg block. What is the acceleration of the object.
horsena [70]

Answer:

4m/s/s

Explanation:

a=f/m

m=5kg

f=20N

20/5=4

(N=kg-m/s/s)

7 0
2 years ago
Read 2 more answers
What type of bulb is unaffected ​
emmasim [6.3K]
<h2>A N S W E R : –</h2>

  • c) Parallel

Nothing happens to the brightness of the light bulbs in the parallel circuit if the power supply is capable of supplying the additional current.

3 0
2 years ago
If a mass of 76 kg acts downward 0.38 m from the axis of rotation on one end of a board and another force of 129 N also acts dow
Semenov [28]

Answer:

y = 2.196 m

Explanation:

Mass, m = 76 kg

distance from axis of rotation, x = 0.38 m

Second Force, F = 129 N

moment arm of the second force, y = ?

Now, equating moments for the equilibrium

So,

m g × x = F x y

76 x 0.38 x 9.81 = 129 x y

y = \dfrac{76\times 0.38\times 9.81}{129}

y = 2.196 m

Hence, the length of the moment arm is equal to 2.196 m.

6 0
3 years ago
A red rubber ball rolls down a hill from rest with an acceleration of 7.8 m/s 2 . How fast is it moving after it has traveled 5
Wittaler [7]

Answer:

8.83m

Explanation:

Given parameters:

  Acceleration  = 7.8m/s²

   Initial velocity = 0m/s

  distance covered  = 5m

Unknown:

Final velocity  = ?

Solution:

The equation to solve this problem with is given as;

    V² = U² + 2aS

V is the final velocity

U is the initial velocity

a is the acceleration

S is the distance

 Input the parameters and solve;

    V² = 0² + 2 x 7.8 x 5 = 78

    V = √78 = 8.83m

5 0
3 years ago
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