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MariettaO [177]
3 years ago
10

6) If Bam was hit by the hand with a force of 1200N. If he has a mass of 81kg, what acceleration did

Physics
1 answer:
bazaltina [42]3 years ago
3 0

Answer:

14.81 m/s^2

Explanation:

f=m×a

1200=81×a

a=1200/81

a=14.81

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If a magnet repels a metal object what can you say about the pole of the magnet and the pole of the object?
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Poles are the same D is the right answer
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Boojho saw a cracker burst at night at a distance from his house. He heard
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The primary reason of seeing the cracker burst and hearing the sound later is because the speed of sound and light. Speed of light is in the vicinity of 3*10^8m,/ sec while the speed of sound is at a distance of 332m/sec. It is similar to lightning that strikes before the sound.

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Akhtar, Kiran and Rahul were riding in a motorocar that was moving with a high velocity on
VikaD [51]

Answer:

According to the law of conservation of momentum:

Momentum of the car and insect system before collision = Momentum of the car and insect

system after collision

Hence, the change in momentum of the car and insect system is zero.

The insect gets stuck on the windscreen. This means that the direction of the insect is

reversed. As a result, the velocity of the insect changes to a great amount. On the other hand,

the car continues moving with a constant velocity. Hence, Kiran’s suggestion that the insect

suffers a greater change in momentum as compared to the car is correct. The momentum of

the insect after collision becomes very high because the car is moving at a high speed.

Therefore, the momentum gained by the insect is equal to the momentum lost by the car.

Akhtar made a correct conclusion because the mass of the car is very large as compared to

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Rahul gave a correct explanation as both the car and the insect experienced equal forces

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4 0
3 years ago
A soap bubble, when illuminated with light of frequency 5.27 Hz × 1014 Hz, appears to be especially reflective. If it is surroun
denis23 [38]

Answer:

1.07004\times 10^{-7}\ m

Explanation:

n_s = Refractive index of bubble = 1.33

f = Frequency of light = 5.27\times 10^{14}\ Hz

c = Speed of light = 3\times 10^8\ m/s

The wavelength of light is given by

\lambda=\dfrac{2n_st}{m-\dfrac{1}{2}}

Wavelength is also given by

\lambda=\dfrac{c}{f}

m = 1 for minimum thickness

\dfrac{c}{f}=\dfrac{2n_st}{m-\dfrac{1}{2}}\\\Rightarrow t=\dfrac{m-\dfrac{1}{2}c}{2n_sf}\\\Rightarrow t=\dfrac{(1-\dfrac{1}{2})\times 3\times 10^8}{2\times 1.33\times 5.27\times 10^{14}}\\\Rightarrow t=1.07004\times 10^{-7}\ m

The minimum thickness is 1.07004\times 10^{-7}\ m

4 0
3 years ago
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