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LiRa [457]
2 years ago
14

How many vertices does a rectangular prism have?

Mathematics
1 answer:
erma4kov [3.2K]2 years ago
8 0

Answer:

"if tom had a cube a rectangular prism and a triangular prism, then the cube has 8 vertices, a rectangular prism has 5 vertices."

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Quadrilateral PQRS is circumscribed about a circle. Line PQ is tangent to the circle at A, line QR at B, line RS at C, and line
yuradex [85]
The sum of the angles of a quadrilateral is 360 degrees.  So P+Q+R is 206, 360 - 206 = 154 degrees, the measure of angle S.

The four triangles, AQB, BRC, CSD, and DPA are all isosceles.  So angle QBA = angle BAQ, etc.  We find QBA = (180-24)/2 or 78 degrees.

RBC = (180-114)/2 = 33 degrees.

180 - (78 + 33) is the measure of angle B:  69 degrees.

The student should be able to see how to calculate the missing information from this.
6 0
3 years ago
All of the following are terminating decimals except _____.<br><br> 1/8<br> 2/5<br> 2/3<br> 17/50
klemol [59]
2/3 is the answer Hope this helps. :)
5 0
3 years ago
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Please help with three questions!! Worth 98 points!!
qwelly [4]

Answer:

Please show us the questions and will help further this discussion.


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3 years ago
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G(b) = 5b- 9 h(b) = (b - 1)^2 Evaluate. (hog)(-6) =
laiz [17]

Given:

The two functions are:

g(b)=5b-9

h(b)=(b-1)^2

To find:

The value of (h\circ g)(-6).

Solution:

We have,

g(b)=5b-9

h(b)=(b-1)^2

We know that,

(h\circ g)(b)=h(g(b))

(h\circ g)(b)=h(5b-9)

(h\circ g)(b)=[(5b-9)-1]^2

(h\circ g)(b)=[5b-10]^2

Putting b=-6, we get

(h\circ g)(-6)=[5(-6)-10]^2

(h\circ g)(-6)=[-39-10]^2

(h\circ g)(-6)=[-49]^2

(h\circ g)(-6)=2401

Therefore, the value of (h\circ g)(-6) is 2401.

7 0
3 years ago
1: 2(y+6)=?<br> 2: 6-(-6+2)=?<br> What is the property of equation?
Citrus2011 [14]
1: 2y+12

2: 6 +6 -2
+12 -2
= 10
5 0
4 years ago
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