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Angelina_Jolie [31]
3 years ago
5

How many atoms are represented by one formula unit of aluminum sulfite, al2(so3)3?

Physics
1 answer:
ratelena [41]3 years ago
4 0
Formula unit is the empirical formula of an ionic or a covalent compound. It is the chemical formula that gives the proportions of the elements present in a certain compound however it does not give the actual numbers or the arrangement of the atoms. For this case, there are 14 atoms of different elements that is involved in the compound.
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A person is lying on a diving board 3.50 m above the surface of the water in a swimming pool. She looks at a penny that is on th
sergij07 [2.7K]

Answer:

1.995 m

Explanation:

Distance of penny as seen by the person = 5 m

Height of person from water surface = 3.50 m

Apparent depth of penny = 5 - 3.50 = 1.5 m

refractive index of water, n = 1.33

real depth / apparent depth = n

real depth = 1.33 x 1.5 = 1.995 m

Thus, the actual depth of water at that point is 1.995 m.

4 0
3 years ago
The position x, in meters, of an object is given by the equation:
LenaWriter [7]

Answer:

The SI units of A, B and C are :

m,\ m/s\ and\ m/s^2                  

Explanation:

The position x, in meters, of an object is given by the equation:

x=A+Bt+Ct^2

Where

t is time in seconds

We know that the unit of x is meters, such that the units of A, Bt and Ct^2 must be meters. So,

  • A=m
  • bt=m

b=\dfrac{m}{s}=m/s

  • Ct^2=m

C=m/s^2

So, the SI units of A, B and C are :

m,\ m/s\ and\ m/s^2

So, the correct option is (B).

3 0
3 years ago
How is sound is different from music how loundness od sound mention some ways to reduce
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3 0
3 years ago
Which of the following objects works by burning fuel to push hot air toward the ground and create thrust to use in lifting off?
olga_2 [115]
Rockets, space stations, space probe 
6 0
4 years ago
Read 2 more answers
In a double-slit interference experiment, the wavelength is λ = 432 nm, the slit separation is d = 0.100 mm, and the screen is d
andrew-mc [135]
In the double-slit interference experiment, the distance of the nth-maximum from the center of the screen is given by
y= \frac{n \lambda D}{d}
where
\lambda is the wavelength
D is the distance between the screen and the slits
d is the distance between the slits

In our problem, 
\lambda=432 nm= 432 \cdot 10^{-9} m
D=42.0 cm=0.42 m
d=0.100 mm=0.1 \cdot 10^{-3} m

By applying the previous formula, we can calculate the distance of the 4th maximum from the center of the screen:
y_4 =  \frac{(4)(432 \cdot 10^{-9} m)(0.42 m)}{(0.1 \cdot 10^{-3}m)}=7.25 \cdot 10^{-3} m

Similarly, the distance of the 8th- maximum is
y_8 = \frac{(8)(432 \cdot 10^{-9} m)(0.42 m)}{(0.1 \cdot 10^{-3}m)}=14.5 \cdot 10^{-3} m

Therefore, the distance between the two maxima is
\Delta y=y_8- y_4 = 14.5 \cdot 10^{-3} m- 7.25 \cdot 10^{-3} m =7.25 \cdot 10^{-3} m = 7.25 mm
5 0
4 years ago
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