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2 years ago

How can a particle that has zero mass (travels at the speed of light) carry energy, and excite cells in our eyeballs?

Physics

1 answer:

11111nata11111 [884]2 years ago

3 0

Answer:

Quantum theory states that electromagnetic radiation travels in discrete amounts with energy

h ν = E = h c / f

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What is the speed of an electromagnetic wave with a frequency of 100 mhz as it travels through a vacuum?

SCORPION-xisa [38]

Answer:

The speed of the wave with a frequency 100 mhz will be $3\times 10^{8}m/sec$

Explanation:

We have given that frequency of light is 100 mhz

We have to find the speed of light in vaccuum

We know that all electromagnetic waves travels in vaccum wth the same speed as the speed of light

And we know that speed of light is equal to $3\times 10^{8}m/sec$

So the speed of the wave with a frequency 100 mhz will be $3\times 10^{8}m/sec$

6 0

3 years ago

A 250 N force pulls on a box horizontally to the right. The box is moving at constant speed.

lana66690 [7]

Answer:

its 34

Explanation:

3 0

3 years ago

A student measures the speed of a rolling ball three times. She adds the measurements and divides by 3. What quantity did the st

Lapatulllka [165]

They calculated the mean value

7 0

3 years ago

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The electron gun in a television tube accelerates electrons (mass = 9.11x10^-31 kg, charge = 1.6 x 10^-19C) from rest to 3 x10^7

stich3 [128]

Answer:

Electric field acting on the electron is 127500 N/C.

Explanation:

It is given that,

Mass of an electron, $m=9.11\times 10^{-31}\ kg$

Charge on electron, $q=1.6\times 10^{-19}\ C$

Initial speed of electron, u = 0

Final speed of electron, $v=3\times 10^7\ m/s$

Distance covered, s = 2 cm = 0.02 m

We need to find the electric field required. Firstly, we will find the acceleration of the electron from third equation of motion as :

$a=\dfrac{v^2-u^2}{2s}$

$a=\dfrac{(3\times 10^7)^2-0}{2\times 0.02}$

$a=2.25\times 10^{16}\ m/s^2$

According to Newton's law, force acting on the electron is given by :

F = ma

$F=9.1\times 10^{-31}\times 2.25\times 10^{16}$

$F=2.04\times 10^{-14}\ N$

Electric force is given by :

F = q E, E = electric field

$E=\dfrac{F}{q}$

$E=\dfrac{2.04\times 10^{-14}}{1.6\times 10^{-19}}$

E = 127500 N/C

So, the electric field is 127500 N/C. Hence, this is the required solution.

8 0

3 years ago

What type of force is needed to accelerate an object?<br> What direction will the object accelerate?

Kay [80]

That just depends on the mass of the object and I think it will accelerate forwards

3 0

3 years ago

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