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ElenaW [278]
2 years ago
15

A spring has a natural length of 28.0 cm. If a 23.0-N force is required to keep it stretched to a length of 36.0 cm, how much wo

rk W is required to stretch it from 28.0 cm to 32.0 cm
Physics
1 answer:
krek1111 [17]2 years ago
4 0

Answer:

0.23 J

Explanation:

k*(36 - 28) = 23

so k = 23/8 N/cm

W = k(32 - 28)²/2 = 23/8 * 4²/2 = 23 N-cm = 0.23 J

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To solve this problem we will use the mathematical definition of the light years in metric terms, from there, through the kinematic equations of motion we will find the distance traveled as a function of the speed in proportion to the elapsed time. Therefore we have to

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Then

14.4Ly = 1.36231609*10^{17} m

If we have that

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x = Displacement

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5 0
3 years ago
A block whose weight is 45 N rests on a horizontal table. A horizontal force of 36 N is applied to the block. The coefficient of
riadik2000 [5.3K]

Answer:

1.5 m/s²

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For the block to move, it must first overcome the static friction.

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Fs = (45 N) (0.42)

Fs = 18.9 N

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∑F = ma

F − N μk = ma

36 N − (45 N) (0.65) = (45 N / 9.8 m/s²) a

6.75 N = 4.59 kg a

a = 1.47 m/s²

Rounded to two significant figures, the block's acceleration is 1.5 m/s².

Usually the coefficient of static friction is greater than the coefficient of kinetic friction.  You might want to double check the problem statement, just to be sure.

6 0
3 years ago
Which equation is used to calculate the magnetic force on a charge moving in a magnetic field?
nadya68 [22]

Answer:

B

Explanation:

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3 years ago
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Sergio039 [100]

Answer:

W = F * s    

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s = distance traveled

[μ M g (1 - sin θ)] cos θ * s = work done in moving sled

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8 0
1 year ago
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