The gravitation force is quartered when two objects' masses are halved without changing their distance.
Gravitational law states that the force of attraction and repulsion between two objects is directly proportional to the product of their masses and inversely proportional to the square of their distance apart.
F=(KM1 M2)/r^2
K= Gravitation force constant
M1M2 = masses of the object
r = distance between objects
When M1 and M2 are halved, it becomes M1/2 and M2/2
F=(K M1/2 x M2/2)/r^2
F=(K (M1 x M2)/4)/r^2
F=(KM1 x M2)/(4r^2 )
Recall
F=(KM1 x M2)/r^2
Therefore
F=F/4
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Склянка с воздухом закрыта «пробкой» из мыльной пены.
Определи, что произойдёт, если склянку частично погрузить в ёмкость с горячей водой?
Выбери правильный вариант ответа.
Мыльная пена будет перемещаться внутрь склянки.
Мыльная пена будет подниматься наружу.
Что произойдёт с давлением воздуха внутри склянки?
Выбери правильный вариант ответа.
Давление не изменится.
и дальнейшее объяснение произошедшего
Может показаться, что воздух в вашей бутылке - просто пустое пространство, но на самом деле это смесь газов. Сила, с которой отдельные молекулы отскакивают от внутренней и внешней стороны бутылки, называется давлением.
Answer:
Given:
1$ = 4q
To Find:
How many quarters are in 20$
Explanation:
To find out how many quarters are in 20$ we need to multiple 4 × 20.
Answer:
The horizontal distance traveled by the projectile is 15.23 m.
Explanation:
Given;
angle of projection, θ = 25⁰
initial velocity of the projectile, u = 15 m/s
time of flight, t = 1.12 s
The the travelling path of the object is calculated as the range of the projectile
Therefore, the horizontal distance traveled by the projectile is 15.23 m.
-- Although it's not explicitly stated in the question,we have to assume that
the surface is frictionless. I guess that's what "smooth" means.
-- The total mass of both blocks is (1.5 + 0.93) = 2.43 kg. Since they're
connected to each other (by the string), 2.43 kg is the mass you're pulling.
-- Your force is 6.4 N.
Acceleration = (force)/(mass) = 6.4/2.43 m/s²<em>
</em> That's about <em>2.634 m/s²</em> <em>
</em>(I'm going to keep the fraction form handy, because the acceleration has to be
used for the next part of the question, so we'll need it as accurate as possible.)
-- Both blocks accelerate at the same rate. So the force on the rear block (m₂) is
Force = (mass) x (acceleration) = (0.93) x (6.4/2.43) = <em>2.45 N</em>.
That's the force that's accelerating the little block, so that must be the tension
in the string.
