Answer:
Step-by-step explanation:
My approach was to draw out the probabilities, since we have 3 children, and we are looking for 2 boys and 1 girl, the probabilities can be Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy. So a 2/3 chance if you think about it, your answer 2/3 can't be correct. If we assume that boys and girls are born with equal probability, then the probability to have two girls (and one boy) should be the same as the probability to have two boys and one girl. So you would have two cases with probability 2/3, giving an impossible 4/3 probability for both cases. Also, your list "Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy" seems strange. All of those are 2 boys and 1 girl, so based on that list, you should get a 100 percent chance. But what about Boy-Girl-Girl, or Girl-Girl-Girl? You get 2/3 if you assume that adjacencies in the (ordered) list are important, i.e., "2 boys and a girl" means that the girl was not born between the boys.
Answer:B A D C
Step-by-step explanation:
Since diameter is double radius you can half that to get radius B is the smallest since it's radius is 3. then we have A because it is 4 then D since its double B that gives us 6 then finally you have C.
Gm, it’s almost night for me
Answer:







Step-by-step explanation:
Rational numbers:
-are all numbers you can write as a quotient of integers
, 
-include terminating decimals. For example, 
-include repeating decimals. For example, 
Irrational numbers:
-have decimal representations that neither terminate nor repeat. For example, 
-cannot be written as quotients of integers
A)

is false. There is no solution.
B)

is false. There is no solution.
C)

is
true. It has infinite solutions.
D)

is
true. It has infinite solutions.
E)

is false. There is no solution.