Since he must not exceed 8 hours driving in a day:
Let the distance of the picnic be = x km.
Therefore time for forward journey = x / 60
Return journey = x / 50
The total trip should not exceed 8 hours.
Therefore: x / 60 + x / 50 <= 8. LCM = 300
Taking LCM and multiplying on both sides:
5x + 6x <= 8(300)
11x <= 2400
x <= 2400/11
x <= 218.18
The picnic spot must be less than or equal to 218.18 km.
the answer of the question is tens
Let 'c' represent the number of pictures Chelsea took.
Let 's' represent the number of pictures Sonya took.
For last year's Thanksgiving, c + s = 236
For this year's Thanksgiving, let 'x' represent the number of photos taken in total. x = c + s, where c and s are two integers that are the same (c = s).
And we know that for both years, c + s + x = 500.
As we know that c + s is already 236 from last year, we can remove c + s from the equation in bold and replace it with 236 instead.
236 + x = 500.
Now we have to isolate the x term.
x = 500 - 236
x = 264.
We know that x = c + s, where c and s are the same, so we can just use one of the variables and double it (so you either get 2c or 2s - it doesn't matter which one you pick because they're both the same).
2c = 264
c = 132
c = s
s = 132.
Both took 132 pictures this year.
Step-by-step explanation:
<u>Given </u><u>:</u><u>-</u>
And we need to solve the equation using Substituting method . So on taking the first equation ,
<u>Put </u><u>this</u><u> </u><u>value</u><u> </u><u>in </u><u>(</u><u>ii)</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Put </u><u>this</u><u> </u><u>Value</u><u> </u><u>in </u><u>(</u><u>I)</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Hence</u><u> the</u><u> </u><u>Value</u><u> </u><u>of </u><u>x </u><u>is </u><u>2</u><u>1</u><u> </u><u>and </u><u>y </u><u>is </u><u>(</u><u>-</u><u>6</u><u>)</u><u> </u><u>.</u>