Answer:
about -1.26 m/s²
Explanation:
The acceleration can be found from the formula ...
a = (v2² -v1²)/(2d)
Here, we have the initial velocity v1=23 m/s, the final velocity v2=0, and teh distance d=210 m. Using the formula, we find the acceleration to be ...
a = (0 -23²)/2(210) ≈ -1.2595 . . . m/s²
Hi there!
Recall the equation for gravitational potential energy:
U = GPE (J)
m = mass (48 kg)
g = acceleration due to gravity (9.8 m/s²)
h = height (21 m)
Plug in the givens and solve.
A) 20 m
<h3>What is called magnitude of displacement?</h3>
The magnitude of displacement is defined as the shortest distance between the initial and final position of the object.
For a particle in motion, the magnitude is either less than or equal to the distance travelled.
Also,
Velocity is simply defined as the rate of change of displacement with time.
Mathematically, it can be expressed as:
Velocity = displacement / time
According to the question,
The following data were obtained:
Time = 5 s
Velocity = 4 m/s
Displacement =?
Velocity = displacement / time
4 = d / 5
D = 4 × 5
D= 20 m
Hence,
20 m is the magnitude of the displacement of the object after it travelled for five seconds.
Learn more about magnitude of the displacement here:
brainly.com/question/10919017
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Answer:
Explanation:
We shall apply here Doppler's effect in optics . The formula is as follows
Δλ is change in wavelength , λ is original wavelength , v is velocity and c is velocity of light
Δλ = 685 - 590 = 95 nm
λ = 685
95 / 685 = v / 3 x 10⁸
v = .416 x 10⁸ m / s
= 4.16 x 10⁷ m /s