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Bas_tet [7]
3 years ago
14

A wrecking ball of mass 500 kg hangs form a crane by a cable of length 25 mit

Physics
1 answer:
Ne4ueva [31]3 years ago
5 0

Given :

A wrecking ball of mass 500 kg hangs form a crane by a cable of length 25 m

this wrecking ball is released from an angle of 40 degrees.

To Find :

The height  from the lowest point of the arc.

Solution :

From the attached image we have to find the value of  h.

So,

cos \ 40^o = \dfrac{L-h}{L}\\\\0.76=\dfrac{25-h}{25}\\\\h = 25( 1- 0.76)\\\\h = 6 \ m

Hence, this is the required solution.

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To overcome an object's inertia, it must be acted upon by __________.
Nastasia [14]

Correct answer choice is :


C) Force


Explanation:


In physics, a force is any cooperation that, when unrestricted, will vary the motion of an object. A force can create an object with mass to alter its velocity to accelerate. Force can also be defined intuitively as a push or a pull. A force acting on an object may create the object to alter shape, to start moving, to stop moving, to stimulate or decelerate. When two objects communicate with each other they exert a force on each other, the forces are just in size but different in direction.

6 0
4 years ago
Read 2 more answers
Step by step process on how to solve this problem
rusak2 [61]

<u>Step-1:</u>  Remember or look up the formula for the force of gravity between two objects.    F = G · m₁ · m₂ / R²

<u>Step-2:</u>  Remember or look up the value of G.<em> </em> G = 6.67 x 10⁻¹¹ m³·kg/s²

<u>Step-3: </u> Write the numbers you know into the formula.

(1.989 x 10²⁰ Newtons) =

(6.67 x 10⁻¹¹ mtr³·kg/s²) · (5.9742 x 10²⁴ kg) · (moon mass) / (3.84 x 10⁸ mtr)²

<u>Step-4:</u>  Sit back, relax, take your time, look this mess over, carefully, end-to-end, and decide how to solve it for (moon mass) .

<u>Step-5:</u> Divide each side by (6.67x10⁻¹¹mtr³·kg/s²)·(5.9742x10²⁴kg)/(3.84x10⁸mtr)²:

Moon mass =

(1.989x10²⁰ Newtons)·(3.84x10⁸ mtr)²/(6.67x10⁻¹¹ mtr³·kg/s²)·(5.9742x10²⁴ kg)

<u>Step-6: </u> Crunch the numbers.  Be careful to KEEP all the units as you go along. When you're done, the units of your answer will be the first instant indication if you made a mistake.  You're looking for the MASS of the moon.  If the answer doesn't have units of 'kg', then that'll be an immediate red flag, telling you that there's been a mistake somewhere.

Moon mass =

(1.989x10²⁰ Newtons)·(3.84x10⁸ mtr)²/(6.67x10⁻¹¹ mtr³·kg/s²)·(5.9742x10²⁴ kg)

Collect the numbers, and collect the units:

Moon mass = (1.989x10²⁰ · (3.84x10⁸)² / (6.67x10⁻¹¹ · 5.9742x10²⁴)

(kg-mtr/s² · mtr²)/(mtr³·kg/s² · kg)

Moon mass = (1.989 · 3.84² x 10³⁶) / (6.67 · 5.9742 x 10¹³)

(kg-mtr/s² · mtr²)/(mtr³·kg/s² · kg)

Moon mass = 0.736 x 10²³ kg

Moon mass = 7.36 x 10²² kg

<u>Step 7: </u> Look it up in a book or online.  See if you're anywhere close.

When I search "moon mass" on Floogle, the first hit says

" 7.348 x 10²² kg " .

yay !  I'm satisfied.

6 0
3 years ago
You want to go swimming, but there is no lifeguard at the beach right now. You are not a good swimmer. The safest thing to do in
saw5 [17]

Answer:

the 1, 3, also fourth

Explanation:

here you goo

3 0
3 years ago
THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!! THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THAN
Karo-lina-s [1.5K]

Answer:

450km because this night founder

6 0
3 years ago
Read 2 more answers
9. Una jeringa contiene cloro gaseoso, que ocupa un volumen de 95 mL a una presión de 0,96 atm. ¿Qué presión debemos ejercer en
masha68 [24]

Answer:

2.61 atm

Ley de Boyle

Explanation:

P_1 = Presión inicial = 0.96 atm

P_2 = Presión final

V_1 = Volumen inicial = 95 mL

V_2 = Volumen final = 35 mL

En este problema usaremos la ley de Boyle.

\dfrac{P_1}{P_2}=\dfrac{V_2}{V_1}\\\Rightarrow P_2=\dfrac{P_1V_1}{V_2}\\\Rightarrow P_2=\dfrac{0.96\times 95}{35}\\\Rightarrow P_1=2.61\ \text{atm}

La presión ejercida sobre el émbolo para reducir su volumen es de 2.61 atm.

4 0
3 years ago
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