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2 years ago

3. If a 2.0-kilogram mass is raised 0.050 meter

Physics

1 answer:

statuscvo [17]2 years ago

8 0

The work done on the mass is approximately 1J

<h3>How to calculate work done on mass</h3>

From the question, we are to determine the work done on the mass

The work done can be calculated from the formula for Potential energy

Work done = P.E = mgh

Where m is the mass

g is the acceleration due to gravity (g = 10 m/s²)

h is the height

From the question,

m = 2.0 kg

h = 0.050 m

Putting the values into the question, we get

Work done = 2.0 × 10 × 0.050

Work done = 1 J

Hence, the work done on the mass is approximately 1J

Learn more on how to calculate work done here: brainly.com/question/14460830

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Explain an example of how energy is transferred from one form to another

scoray [572]

Answer:

read the explanation

Explanation:

Purchased electricity is fed into our TVs and is converted to light and sound.

Electricity goes into an electric bulb and is converted to visible light and heat energy.

Chemical Energy is converted to Electrical Energy (stove)

Chemical food energy is converted to Energy to Work (person running).

6 0

3 years ago

Suppose you exert a 25-N force to lift a ball 0.4 m in 2 s. How much work is done?

Sergio [31]

work is force x distance = 25 x 0.4

= 2.5x4 = 10joules

pwer would be 10j/2s watts .... 5 watts

3 0

3 years ago

What are the two requirements of a circuit so that current will flow?

antoniya [11.8K]

Answer:

-The battery-the power source

-Closed conducting loop

Explanation:

-To produce an electric current, the following requirements must be met:

-A battery-This is the energy source than will do work on the charge thus moving from a low energy location to high energy location.

-Closed Conducting Loop-The loop is usually made of copper wires due to their high electric conductivity.

8 0

3 years ago

Our eyes can see light with an angular resolution of about 1’—equivalent to about a third of a millimeter at arm’s length. Suppo

olya-2409 [2.1K]

Answer:

We would not be able to make our way around the earth's surface, to read, to sculpt or to create technology because we cannot see!

Explanation:

The minimum angular separation that can be distinguished by an eye gives the angular resolution of the eye.

Given that the Angular resolution with infrared radiation is = $1.0^0$ equal to $60'$

This resolution is very much greater than that of the eye $(1')$

The angular resolution that our eyes can see is about $\frac{1}{3}mm$ at arms length

Angular resolution of infrared = $\frac{1}{3} * 60 = 20mm$ at arms length

We therefore cannot read, sculpt or create technology because we cannot see.

7 0

3 years ago

A uniform disk of mass M = 4.9 kg has a radius of 0.12 m and is pivoted so that it rotates freely about its axis. A string wrapp

AlekseyPX

Answer:

(A) 2.4 N-m

(B) $0.035kgm^2$

(D) 1741.13 J

(E) 725.481 rad

Explanation:

We have given mass of the disk m = 4.9 kg

Radius r = 0.12 m, that is distance = 0.12 m

Force F = 20 N

(a) Torque is equal to product of force and distance

So torque $\tau =Fr$ , here F is force and r is distance

So $\tau =20\times 0.12=2.4Nm$

(B) Moment of inertia is equal to $I=\frac{1}{2}mr^2$

So $I=\frac{1}{2}\times 4.9\times 0.12^2=0.035kgm^2$

Torque is equal to $\tau =I\alpha$

So angular acceleration $\alpha =\frac{\tau }{I}=\frac{2.4}{0.035}=68.571rad/sec^2$

So initial angular speed $\omega _{0}=0rad/sec$

Time t = 4.6 sec

From first equation of motion we know that $\omega =\omega _0+\alpha t$

So $\omega =0+68.571\times 4.6=315.426rad/sec$

(D) Kinetic energy is equal to $KE=\frac{1}{2}I\omega ^2=\frac{1}{2}\times 0.035\times 315.426^2=1741.13J$

(E) From second equation of motion

$\Theta =\omega _0t+\frac{1}{2}\alpha t^2=0\times 4.6+\frac{1}{2}\times 68.571\times 4.6^2=725.481rad$

3 0

3 years ago